Write this Equation using Mathematica

[EngWiPy]

Hello everyone,

I have the following equation, and I want to write it using mathematica:

where:

and:

Where $$\Psi$$ is the tricomi's confluent hypergeometric function, built-in Mathimatica as HypergeometricU[ , , ].
Can anyone help me, please?
Thanks in advance
Best regards

 

[Dale]

I don't understand. What exactly is the difficulty? It seems straightforward, especially since you already know HypergeometricU.

 

[EngWiPy]

I don't understand. What exactly is the difficulty? It seems straightforward, especially since you already know HypergeometricU.

Than you DaleSpam for replying. Actually, I took this equation from a paper which plotted it. When I tried to so do, the program gave may little bit different results, so, I thought that I wrote the program incorrectly using Mathematica. But after I posted this thread, I solved the problem, which was a matter of signs and powers.

Sorry for that, and thanks again.

Regards

 

[Mike^now]

how we can find the law of formation of sequence in mathimatica? pleasezz help.

 

[Dale]

Hi Mike^now, welcome to PF

What does "law of formation of sequence" mean?

 

[Mike^now]

it is a general rule to write a sequence. like 1/2,1/4,1/8/1/16,1/32... has a general rule (1/2^n. where n = number of term.

 

[Dale]

That is not possible to do in general. No matter how many terms you write out, unless you already know the rule, you cannot know the next term.

For example, with the sequence you gave the next number could be 1/32, or the sequence could be cyclic and the next number could be 1/2 again, or it could be a bitshift of a floating point number with 5 bits of precision so that the next term is 0, etc.

 

[Dale]

Hmm, apparently they have a function which tries anyway:
FindSequenceFunction

 

[Mike^now]

This function does not provide general term of sequence ( 4/3,5/4,6/5,7/6...)

By writting FindSequenceFunction[{1, 4/3, 5/4, 6/5, 7/6, 8/7, 9/8}, n] produce as it is. no result.

even i tried sequence starting from 0 as well as from 1 and still it does not produce any formula of general term.

 

[Dale]

Well, that does not surprise me. As I said, it is fundamentally an impossible question. It is pretty impressive that it ever works.