- #1

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- Homework Statement
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- Relevant Equations
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Adopt the speed of light equals one.

Calls ##cos = c##, ##sin = s##

$$ux' = \frac{v-uc}{1-uvc}$$

$$uy' = \frac{us}{\gamma(1-uvc)}$$

$$tan \theta' = uy' / ux' = \frac{us}{\gamma(v-uc)}$$

So that's basically my solution. The problem is: The answer is ##\frac{us}{\gamma(v+uc)}##. Now, i can't understand why there is a plus sign instead my minus sign. Seems that, to got the answer provided, it was assumed that, for example, ##ux' = \frac{v+uc}{1+uvc}##. Certainly wrong, since if v = uc, ux' should be zero.

So my question is, maybe my answer is right, the problem is that i assumed v to the right and the author assumed v to the left? Or did i a mistake? WHere?