Which Product Won't Be Obtained in a Wurtz Reaction?

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Homework Statement


Which one of the following products will not be obtained in the given Wurtz reaction?
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The Attempt at a Solution


Well, (a) will definitely be the major product. We know that this reaction may proceed by a free radical or an ionic mechanism. But what's that got to do with the C-14 shifting position inside the ring? Any help?
 

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It might help to draw out the resonance structures of the radical/ionic intermediate.
 
TeethWhitener said:
It might help to draw out the resonance structures of the radical/ionic intermediate.
Well, won't that conversion require additional energy? Do we presume it is available?
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baldbrain said:
Well, won't that conversion require additional energy?
Why? Maybe draw the hydrogens explicitly.
 
TeethWhitener said:
Why? Maybe draw the hydrogens explicitly.
What difference does that make? Won't THIS ##\downarrow## require additional energy?
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baldbrain said:
Won't THIS ↓↓\downarrow require additional energy?
Google "allyl radical."
 
TeethWhitener said:
Google "allyl radical."
****, you're right...I keep forgetting that.
 
I don't know why, but I still don't have a keen eye spotting the allyl radical. Get me?
 
You might remember I stumbled upon this 'allyl' thingy even in that "same SN1 & SN2 product" problem.
Anyway, Thanks again.:smile:
 
baldbrain said:
I don't know why, but I still don't have a keen eye spotting the allyl radical.
It's not a bad idea to have the possibility of allylic resonance in the back of your mind whenever you see a double bond. Other than that, I'm not sure there are any tricks to remembering it.
 
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I forgot to mention that the answer would be (d). You might've already guessed that.
 
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