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You are traveling on a straight road with constant velocity

  1. Jun 22, 2015 #1
    1. The problem statement, all variables and given/known data
    At the beginning of a 10 sec. interval your position is measured to be 80 ft East with respect to a reference object. At the end of the 10 sec. interval your position is measured to be 965 ft East with respect to the same reference object.
    Determine your velocity at t = 3.45 sec.
    Determine your velocity at t = 6.9 sec.
    Calculate the area under the entire V-t graph. What does this area respresent?

    2. Relevant equations
    m(slope) = v = change in x divided by change in t = Xf - Xo/tf - to =
    965ft - 80ft/10 sec- 0sec = 885ft/10sec = 88.5met/sec. East

    3. The attempt at a solution
    Area = Vot = 10 sec times 88.5 met/sec = 885 meters This represents the displacement of the car.
    The velocity of the car at t = 3.45 sec and at t = 6.9 sec is 88.5 met/sec.
     
  2. jcsd
  3. Jun 22, 2015 #2

    phinds

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    I assume your question is whether or not you got the right answers, yes? It's always a good idea to state your question, even if it seems obvious to you.

    It looks good to me.
     
  4. Jun 22, 2015 #3
    I did not understand this ft-meter transformation
     
  5. Jun 22, 2015 #4
    Yes, I just wanted to make sure I did it right. Thanks.
     
  6. Jun 22, 2015 #5
    It was a typo I made.
     
  7. Jun 22, 2015 #6

    phinds

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    Good catch. Probably just a typo but I breezed right past it.
     
  8. Jun 22, 2015 #7
    I have a question.Why we ignore acceleration of car.Maybe car is accelerating ?
     
  9. Jun 22, 2015 #8
    The car is not accelerating, it's going at a constant velocity of 88.5 met/sec.
     
  10. Jun 22, 2015 #9

    vela

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    Read the thread title.
     
  11. Jun 22, 2015 #10
    Ooppsss Sorry
     
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