You are traveling on a straight road with constant velocity

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Homework Help Overview

The problem involves determining the velocity of a car traveling on a straight road with constant velocity over a specified time interval, based on given position measurements. The context includes calculating the area under a velocity-time graph and understanding its significance.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of velocity based on position changes and question the conversion between feet and meters. There are inquiries about the assumption of constant velocity and whether acceleration should be considered.

Discussion Status

Some participants express uncertainty about the correctness of the calculations and the assumptions made regarding acceleration. There is a mix of validation and questioning of the initial approach, with no clear consensus reached on the assumptions involved.

Contextual Notes

Participants note the potential for confusion regarding unit conversions and the implications of assuming constant velocity without considering possible acceleration.

Tonia
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Homework Statement


At the beginning of a 10 sec. interval your position is measured to be 80 ft East with respect to a reference object. At the end of the 10 sec. interval your position is measured to be 965 ft East with respect to the same reference object.
Determine your velocity at t = 3.45 sec.
Determine your velocity at t = 6.9 sec.
Calculate the area under the entire V-t graph. What does this area respresent?

Homework Equations


m(slope) = v = change in x divided by change in t = Xf - Xo/tf - to =
965ft - 80ft/10 sec- 0sec = 885ft/10sec = 88.5met/sec. East

The Attempt at a Solution


Area = volt = 10 sec times 88.5 met/sec = 885 meters This represents the displacement of the car.
The velocity of the car at t = 3.45 sec and at t = 6.9 sec is 88.5 met/sec.
 
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I assume your question is whether or not you got the right answers, yes? It's always a good idea to state your question, even if it seems obvious to you.

It looks good to me.
 
Tonia said:
885ft/10sec = 88.5met/sec. East
I did not understand this ft-meter transformation
 
Yes, I just wanted to make sure I did it right. Thanks.
 
It was a typo I made.
 
RyanH42 said:
I did not understand this ft-meter transformation
Good catch. Probably just a typo but I breezed right past it.
 
I have a question.Why we ignore acceleration of car.Maybe car is accelerating ?
 
RyanH42 said:
I have a question.Why we ignore acceleration of car.Maybe car is accelerating ?
The car is not accelerating, it's going at a constant velocity of 88.5 met/sec.
 
Read the thread title.
 
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  • #10
vela said:
Read the thread title.
Ooppsss Sorry
 

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