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You are traveling on a straight road with constant velocity

  • Thread starter Tonia
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1. Homework Statement
At the beginning of a 10 sec. interval your position is measured to be 80 ft East with respect to a reference object. At the end of the 10 sec. interval your position is measured to be 965 ft East with respect to the same reference object.
Determine your velocity at t = 3.45 sec.
Determine your velocity at t = 6.9 sec.
Calculate the area under the entire V-t graph. What does this area respresent?

2. Homework Equations
m(slope) = v = change in x divided by change in t = Xf - Xo/tf - to =
965ft - 80ft/10 sec- 0sec = 885ft/10sec = 88.5met/sec. East

3. The Attempt at a Solution
Area = Vot = 10 sec times 88.5 met/sec = 885 meters This represents the displacement of the car.
The velocity of the car at t = 3.45 sec and at t = 6.9 sec is 88.5 met/sec.
 

phinds

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I assume your question is whether or not you got the right answers, yes? It's always a good idea to state your question, even if it seems obvious to you.

It looks good to me.
 
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885ft/10sec = 88.5met/sec. East
I did not understand this ft-meter transformation
 
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Yes, I just wanted to make sure I did it right. Thanks.
 
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It was a typo I made.
 
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I have a question.Why we ignore acceleration of car.Maybe car is accelerating ?
 
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I have a question.Why we ignore acceleration of car.Maybe car is accelerating ?
The car is not accelerating, it's going at a constant velocity of 88.5 met/sec.
 

vela

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Read the thread title.
 

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