1. The problem statement, all variables and given/known data An 8.5 gram slug is fired East from a 0.357 magnum hand gun held 1.5 meters above the ground. The muzzle velocity (as the projectile leaves the gun) is 1400 ft/sec. The bullet is accelerated at a constant rate as it travels through the 10 cm long barrel. After leaving the barrel, the gun powder force drops to 0. 2 a)  What force does the exploding powder exhaust apply to accelerate the slug? 2 b)  What horizontal force is put on the shooters arm by the gun? Sketch a graph of this force as a function of time. (assume the gun is held fixed) 2. Relevant equations u = initial velocity v = u + at v2 = u2 + 2ad F = ma 3. The attempt at a solution a) Converting to SI units: 1400 ft/sec x 12in/ft = 16800 in/s 16800 in/s x 0.0254m/in = 426.72 m/s 8.5 grams = 0.0085 kg 10 cm = 0.1 m assuming u = 0 m/s 426.722 = 0 + 2(0.1)(a) a = 910449.7920 m/s2 (what the hell?) F = ma F = 0.085(910449.7920) = 7739 N b) Due to Newton's third law, the force exerted by the gun (7739 N) should be the same as on the man's arm. My values are very odd, so I feel like what I've done is incorrect however I can't think of how this is wrong. Thanks for your help.