Zero from which the energy is measured

[ShayanJ]

Consider the famous harmonic oscillator. Now imagine I use my freedom in choosing the origin for the potential and choose, instead of the usual thing, V(x)=\frac{1}{2}m \omega^2 x^2-\frac{1}{2} \hbar \omega, so the TISE becomes:
<br /> -\frac{\hbar^2}{2m}\frac{d^2 \psi}{dx^2}+\frac 1 2 m\omega^2x^2 \psi=(E+\frac{1}{2} \hbar \omega) \psi<br />
So its obvious, that the energy levels become E_n= n\hbar \omega. So now the ground state has zero energy!
But this can't be right. Where is zero-point energy? If it is a physical concept, then it shouldn't depend on our choices. So there should be a way that it shows up here too. But I fail to see that way. Any ideas?
Thanks

 

[mfb]

So now the ground state has zero energy!

So what?
Absolute energy has no meaning in nonrelativistic quantum mechanics. Only energy differences are meaningful, and they stay the same.

 

[dextercioby]

It's actually simpler than that. A constant term to the classical Hamiltonian has no influence on the Hamilton's equations (remember, the Hamiltonian is under a differential operator wrt q,p) in the eom. The quantum case is simple. The constant produces a complex (unit modulus) time-dependent exponential, hence brings no involvement to the spectral equation which only considers stationary states.

 

[ShayanJ]

So zero-point energy is meaningless?
But that means its completely meaningless to talk about zero-point energy and say:" This is one difference between classical and quantum mechanics where the system can never have zero energy" which is something you can find in most introductory QM textbooks.
So what's all the stuff in here ? No meaning at all?!
What about the minimum energy required by Uncertainty principle?

 

[dextercioby]

It's actually not like that at all. The hbaromega/2 is mandatory in the quantum theory, can't get rid of it. It's due to the fact that q and p are non-commuting variables *operators/matrices*, The quantized harmonic oscillator has thus a 'residual' energy of purely quantum nature.

 

[ShayanJ]

It's actually not like that at all. The hbaromega/2 is mandatory in the quantum theory, can't get rid of it. It's due to the fact that q and p are non-commuting variables *operators/matrices*, The quantized harmonic oscillator has thus a 'residual' energy of purely quantum nature.

That's exactly my point. Every quantum system should contain that. But where is it in the problem I mentioned(with the potential I chose)?

 

[dextercioby]

It's in the squared coordinate term of the potential. The constant you put by hand can be <gauged away/absorbed> into a time-dependent phase factor.
About the comment <every quantum system should have that>. Well, not really. This <residue> is particular to the squared coordinate potential energy, hence to the harmonic oscillator (or to any Hamiltonian for which there's canonic transformation to bring it to the p^2 +q^2 form). This particularity is then carried forward to free field QFT.

 

[ShayanJ]

It's in the squared coordinate term of the potential. The constant you put by hand can be <gauged away/absorbed> into a time-dependent phase factor.
About the comment <every quantum system should have that>. Well, not really. This <residue> is particular to the squared coordinate potential energy, hence to the harmonic oscillator (or to any Hamiltonian for which there's canonic transformation to bring it to the p^2 +q^2 form). This particularity is then carried forward to free field QFT.

I get it, thanks.
And about that comment. I don't understand why you say this is particular to the squared potential. Uncertainty principles requires it to exist for all quantum systems.

 

[mfb]

So zero-point energy is meaningless?
But that means its completely meaningless to talk about zero-point energy and say:" This is one difference between classical and quantum mechanics where the system can never have zero energy" which is something you can find in most introductory QM textbooks.
So what's all the stuff in here ? No meaning at all?!
What about the minimum energy required by Uncertainty principle?

The zero-point energy is the difference to the lowest point in the potential (=the classical ground state), and that does not change with your energy shift.