Zinc Reacting with Hydrochloric Acid: STP Conditions

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SUMMARY

The reaction of zinc (Zn) with concentrated hydrochloric acid (HCl) produces hydrogen gas (H2) and zinc chloride (ZnCl2) under standard temperature and pressure (STP) conditions, defined as 101.3 kPa and 0°C. The balanced chemical equation is 2 HCl + Zn → ZnCl2 + H2. When 5.00 g of zinc reacts completely, the volume of hydrogen gas produced is calculated to be 1.703 liters using the ideal gas law equation, PV = nRT, with R set to 8.314 J/(mol K).

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Homework Statement


Base metal zinc (Zn) reacts with concentrated hydrochloric acid (HCl) forming gaseous hydrogen and zinc chloride.
STP conditions: pressure p = 101,3 kPa , temperature t = 0C.
The equation of state for ideal gas: pV = nRT
R = 8,314 J /(mol K)

Homework Equations


Write down the chemical reaction formula and calculate the volume of the gaseous hydrogen (H2) formed at STP conditions when 5,00 g of zinc reacts completely.

The Attempt at a Solution


2 HCl + Zn -----> ZnCl2 + H2
5g-----------------mH2
65.41g------------2g
mH2=10/65.41=0.152g.
nH2=mH2/MH2=0.152/2=0.076mol

PV=nRT
V=nRT/P
V=(0.076*8.314*273.15)/101300
V=1.703*10e-3 m3
V=1.703L.
 
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Looks correct. Pay attention to significant figures. Not that they matter much, but they are being checked.
 

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