Calculate the molarities of CH3COOH and CH3COO-

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Discussion Overview

The discussion revolves around calculating the molarities of acetic acid (CH3COOH) and its conjugate base acetate (CH3COO-) in a buffer solution after the addition of sodium hydroxide (NaOH). The context includes the initial concentrations and volumes of the components involved in the reaction.

Discussion Character

  • Homework-related, Mathematical reasoning, Conceptual clarification

Main Points Raised

  • One participant requests assistance in calculating the molarities of CH3COOH and CH3COO- after mixing specific volumes of acetic acid, distilled water, and NaOH.
  • Another participant notes that the addition of NaOH will alter the equilibrium of acetic acid by reacting with it, prompting the need to find new concentrations after equilibrium is established.
  • A participant expresses difficulty in understanding the chemistry involved and requests a detailed explanation.
  • One participant suggests finding the initial concentrations of hydroxide and acetic acid, indicating that the hydroxide will react with acetic acid and proposing a method to calculate the new concentrations.
  • Another participant reminds that the concentration of hydroxide should be added to the conjugate base concentration of acetic acid.
  • A participant expresses gratitude for the assistance provided.

Areas of Agreement / Disagreement

Participants appear to share a common understanding of the need to calculate concentrations after the reaction, but there is no consensus on the specific steps or methods to achieve this, as some participants express confusion and seek clarification.

Contextual Notes

The discussion does not resolve the mathematical steps required to find the new concentrations, and there are assumptions regarding the equilibrium that remain unaddressed.

surahyot
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Can someone help me how to calculate the molarities of CH3COOH and CH3COO- in a buffer solution containing 40.00 ml of 0.100M acetic acid, 10.00 ml of distilled water and 30.00ml of 0.100M NaOH?
 
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What will happen after sodium hydroxide, which dissociates completely in water, is added? The hydroxide will alter the equilibrium of the acetic acid by reacting with _______?

You need to find the new concentrations after the equilibrium.
 
Last edited:
Still don't get it. Chemistry is a nightmare for me.Can someone explain in detail.:frown:
 
Thus the first thing to do is to find the initial concentrations of both OH and acetic acid.

The base, OH- (which dissociates completely), will react with the acetic acid directly. So subtract the original concentration of acetic acid by the concentration of hydroxide anion. Using this concentration substitute into the equilibrium equation and find the rest of the concentrations.

Hope this answers your question.
 
don't forget to add the concentration value of OH- to the conjugate base concentration of the acetic acid.
 
thanks a lot
 

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