View Full Version : columb's law
1. The problem statement, all variables and given/known data
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?
2. Relevant equations
3. The attempt at a solution
not sure why this wouldn't work 2.3 N = (8.99 x 10^9 * Q2)/ .25^2
should that work? and would the sign be + or -?
thanks.
olgranpappy
Jan8-08, 09:47 PM
1. The problem statement, all variables and given/known data
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?
2. Relevant equations
3. The attempt at a solution
not sure why this wouldn't work 2.3 N = (8.99 x 10^9 * Q2)/ .25^2
should that work? and would the sign be + or -?
thanks.
you want the force to be attractive, as stated in the problem. do like charges attract or repel?
like charges repel. however, is my formula equation correct?
Mindscrape
Jan8-08, 09:56 PM
You are missing a charge, remember
F = k \frac{qQ}{r^2}
Okay, I see, so then I solve for Q2, correct?
which shows now 2.3 N = ((8.99 x 10^9) * (2.3) * (Q2) )/ .25^2
i get something like: -4.57 x 10^-12 C
Mindscrape
Jan8-08, 11:36 PM
You should solve for what you want algebraically before you put in numbers. It is a lot easier that way. So you are right, you want the value of the other charge.
q_2 = \frac{r^2 F}{kq_1}
in terms of the numbers that would be... (you do it)
*note: you made a mistake for the value of the first charge. Also note that I just gave you the magnitude of the charge, you will have to figure out the sign.
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