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sapiental
Feb26-08, 09:54 PM
1. The problem statement, all variables and given/known data

a) How many bit strings are there of length 8?

b) How many bit strings are there of length 8 which begins with 2 1's?

2. Relevant equations

Product Rule

3. The attempt at a solution

a) Since a bit string is either 0 or 1 there are two possibilities for each one. By the rule of products 2^8 = 256 bit strings.

c) the first two choices are fixed so its 11(0/1)(0/1)(0/1)(0/1)(0/1)(0/1)

2^6 = 64 possible different bit strings.

when u allow the preceding 1 to change u basically double the 64 combinations and allowing the first one u quadruple it getting back to the original 256.


Could someone please confirm my result. Danke!

jhicks
Feb26-08, 10:19 PM
In short: Yes.