Calculating the Stationary Value of J Integral

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The discussion focuses on calculating the stationary value of the J integral, defined as J = ∫ab dt L(...; xi; ˙xi; ...; t) under the constraint φ(...; xi, ˙xi; ...; t) = 0. The solution involves the free variation of the integral I = ∫ab dt F, where F = L(...; xi; ˙xi; ...; t) - λ(t)φ(...; xi, ˙xi; ...; t). The discussion suggests using Lagrange multipliers to approach the problem effectively.

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Homework Statement

Show the stationary value of,

[tex]J = \int_{a}^{b} dt~L(...;x_i;\dot{x}_i;...;t)[/tex]

subject to the constraint,

[tex]\phi(...;x_i,\dot{x}_i;...;t) = 0[/tex]

is given by the free variation of,

[tex]I = \int_{a}^{b} dt~F = \int_{a}^{b}dt~\left[L(...;x_i;\dot{x}_i;...;t)-\lambda(t)\phi(...;x_i,\dot{x}_i;...;t)\right][/tex]

The attempt at a solution

Not sure where to start here; or really what's wanted... Do I start with [itex]J[/itex] and [itex]\phi[/itex] and get to the variation of [itex]I[/itex]?

Is the free variation of [itex]I[/itex] given by,

[tex]\delta I = \int_{a}^{b}dt~\left[\frac{\partial F}{\partial x} \delta x \frac{\partial F}{\partial \dot{x}} \delta{\dot{x}}\right][/tex] ?
 
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It's been a while since I did this, but you may want to take a look at "Lagrange multipliers", that might get you on track.
 

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