Is there a general way of writing the Lorentz transformation for (2+1) dimension or higher, in terms of its hyperbolic angle, sinh and cosh ?
Mentz114
Jun16-09, 05:59 PM
This is a boost in the x direction with velocity \beta
\left[ \begin{array}{ccc}
\cosh(\beta) & \sinh(\beta) & 0 \\\
\sinh(\beta) & \cosh(\beta) & 0 \\\
0 & 0 & 1 \end{array} \right]
Peeter
Jun16-09, 06:08 PM
Lut, isn't that a boost in the -x direction?
touqra
Jun16-09, 06:57 PM
This is a boost in the x direction with velocity \beta
\left[ \begin{array}{ccc}
\cosh(\beta) & \sinh(\beta) & 0 \\\
\sinh(\beta) & \cosh(\beta) & 0 \\\
0 & 0 & 1 \end{array} \right]
What about in a 2D plane ? I don't think it's just a matrix multiplication between x-axis boost and y-axis boost, or is it ? At least, addition of velocity is not the case.
jtbell
Jun16-09, 08:11 PM
For three dimensions (but without hyperbolic angles) see Wikipedia (http://en.wikipedia.org/wiki/Lorentz_transformation). Scroll down to where it says "More generally for a boost in an arbitrary direction."
Rasalhague
Jun16-09, 08:49 PM
Lut, isn't that a boost in the -x direction?
Yes, unless I'm mistaken, a boost in the positive x direction (output frame moving in the positive x direction wrt the input frame) has minus signs in front of the sinhs. Also, I think the input for cosh and sinh should be the velocity parameter or "rapidity", sometimes written phi, which is artanh(beta) = artanh(v/c), rather than the velocity itself - artanh being the inverse hyperbolic tangent.
http://en.wikipedia.org/wiki/Rapidity
DrGreg
Jun16-09, 09:51 PM
Under the convention that a 4-vector is written as