Can you use momentum conservation to support your friend's case in court?

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving a car accident where momentum conservation is considered to support a friend's case in court. The scenario includes two cars colliding and sliding together, with specific details about their masses, the distance they slid, and the angle of their movement. Participants are exploring how to apply principles of momentum and kinetic friction to analyze the situation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to apply momentum conservation principles and are questioning the correct use of formulas related to momentum and kinetic energy. There is uncertainty about how to calculate the initial velocity and the role of the coefficient of kinetic friction in the problem.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on how to approach the problem. Some guidance has been offered regarding working backwards from the final conditions to determine initial velocities and forces acting on the cars. However, there is no explicit consensus on the methods to be used.

Contextual Notes

Participants note the challenge of working with the given final conditions to find initial values, which is a reversal of typical problem-solving scenarios. There is also mention of the advanced nature of the problem relative to the participants' current understanding of physics.

Gregory
Messages
2
Reaction score
0
I have a problem, and I have no clue where to start- anyone have any help?

Your friend has been in a car accident and wants your help. She was driving her 1265-kg car north on Oak Street when she was hit by a 925-kg compact car going wast on Maple Street. The cars stuck together and slid 23.1m at 42° north of west. The speed limit on both streets is 50 mph (22 m/s). Your friend claims that she wasn't speeding, but that the other car was. Can you support her case in court? Assume that momentum was conserved during the collision and that acceleration was constant during the skid. The coefficient of kinetic friction between the tires and the pavement is 0.65.

Any help would be very appreciated... I am using the formula p=mv and p(A1)=P(1)sin x (The (A1) and (1) are subscripts)

I figured out that
Car 1 (Westward)
P(A) = (v*925kg)*(sin x) (again, (A) is a subscript of p)

Car 1 (Northward)
P(A) = (v*1265kg)*(cos x) (again, (A) is a subscript of p)

but, I'm not sure if that's even correct..

I was hoping F(f)=uF(N) would be useful, as its the only forumula I could find that uses the coefficient of friction (The (f) and (N) are subscripts, the "u" stands for the coefficient of friction- I couldn't find the right symbol for it)

I have a few diagrams drawn, but other than that, I couldn't figure out how to start...
 
Last edited:
Physics news on Phys.org
Hmm...

How would I find the velocity? I was going to use KE=1/2 mv^2; but I can't figure out KE (I'm assuming that's what was being referred to by kinematics)...

I normally wouldn't ask for this much help, but after 2 hours of staring at forumlas with no result, I must admit I'm completely lost.

And, how does the kinetic coefficient come into play in this problem?

Thanks for your help- this is advanced for what I'm learning in school, so I don't have too much background knowledge to help me out..
 
Typically in problems, you are giving the initial conditions and you find the final. In this case, you are given the final conditions and are required to find the initial. So the best idea would be to work backwards. After the cars stuck together, what force was acting on them? Therefore, what acceleration was acting on them? If the final velocity is zero, then what must the initial velocity be? Then what must the momentum right after they hit each other (and before since it is conservered)? Compare this to your initial momentum.
 
Isn't it funny that, even in physics problems, it's the women who usually get into accidents?
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
9K