Kick tush magnetic field/Ampere Problem

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SUMMARY

The discussion centers on calculating the current in two parallel wires that hang at a 6-degree angle due to the magnetic force between them. The wires, each with a mass per unit length of 1.50×10-2 kg/m, are suspended by cords measuring 4.00 cm. To solve the problem, participants suggest using Ampere's law, specifically the formula B = μ0I/2πr, to determine the current necessary to produce the required magnetic field at the distance of the cords. The angle of 6 degrees indicates a horizontal force acting on the wires, which must be accounted for in the calculations.

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  • Basic trigonometry for calculating distances and angles
  • Familiarity with the concept of force between current-carrying wires
  • Knowledge of physical constants such as the permeability of free space (μ0)
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Two long, parallel wires hang by 4.00-cm-long cords from a common axis. The wires have a mass per unit length of 1.50×10-2 kg/m and carry the same current in opposite directions.

What is the current in each wire if the cords hang at an angle of 6-degrees with the vertical?


Basically,,,,,I have no idea how to approach or solve this proble. All I know is the curremt should be positive because the currents in the wires are opposite each other.

aghhh help me please
 
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The only way I can make sense of this is to assume that the 6 degree angle of the cords is because of a force between the two wires.

So: 1. Find the horizontal force on each wire necessary to "lift" the wire to that 6 degree position.
2. Find the distance between the two wires.
3. Find the current necessary to produce that force at that distance.
 


Hi there,

I completely understand your frustration and confusion with this problem. It can be overwhelming to encounter a physics problem that seems complex and difficult to approach. However, with the right approach and understanding of the concepts involved, you can definitely solve this problem.

First, let's break down the given information and the question itself. We have two long, parallel wires hanging from a common axis with 4.00-cm-long cords. The wires have a mass per unit length of 1.50×10-2 kg/m and carry the same current in opposite directions. The question is asking for the current in each wire if the cords hang at an angle of 6-degrees with the vertical.

To solve this problem, we need to use the concept of magnetic fields and Ampere's law. Ampere's law states that the magnetic field created by a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire. In this case, we have two wires with the same current, so we can focus on one wire to find the magnetic field at a certain distance.

To find the magnetic field at the cords' distance from the wire, we can use the formula B = μ0I/2πr, where B is the magnetic field, μ0 is the permeability of free space (a constant value of 4π×10-7 Tm/A), I is the current, and r is the distance from the wire. We can rearrange this formula to solve for the current, which gives us I = 2πrB/μ0.

Now, let's apply this formula to our problem. The distance from the wire to the cords is 4.00 cm, which is equivalent to 0.04 m. The angle between the cords and the vertical is 6 degrees, which means the distance from the wire to the cords is the hypotenuse of a right triangle with a base of 4.00 cm and an angle of 6 degrees. Using trigonometry, we can find that the distance from the wire to the cords is approximately 0.04 m.

Next, we need to find the magnetic field at this distance. We know that the wires have the same current in opposite directions, which means they create opposite magnetic fields. These magnetic fields will cancel each other out, leaving us with a net magnetic field of 0. To find the magnetic field of one wire
 

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