Why Are Some 3 p-Electron States Excluded by the Pauli Principle?

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The discussion centers on the exclusion of certain three p-electron states due to the Pauli exclusion principle. Specifically, the state L=0, S=1/2 (S doublet) is excluded because it violates the principle by having identical quantum numbers for both electrons. The valid configurations identified include L=2, S=1/2 (D doublet), L=1, S=1/2 (P doublet), and L=0, S=3/2 (S quartet). For energy calculations of these states using Slater integrals, further consultation of textbooks or instructors is recommended.

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Kalimaa23
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Greetings,

I've been asked to determine which states are possible with a three p-electron configuration, and to expres their energies with the Slater integrals.

A three p electron state with the same principal quantum number n have the following possibilities :

L=3 excluded by the Pauli principle
L = 2, S=1/2 => D doublet
L = 1, S= 1/2 => P doublet
L = 0 S = 3/2 => S quartet

Now, for some reason L = 0, S = 1/2 => S doublet isn't listed as a possibility, why is this?

Now I'm to expres the energies of these states with slater integrals, but I'm totally at a loss to how I should be doing does. Can anyone point me in the right direction?
 
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Hello,

To answer your question, the reason why L=0, S=1/2 => S doublet is not listed as a possibility is because it violates the Pauli exclusion principle. This principle states that no two electrons can have the same set of quantum numbers, including spin. Since the L and S values are the same for both electrons in this state, it is not allowed.

As for expressing the energies of these states with Slater integrals, I would suggest consulting your textbook or speaking with your instructor for guidance. The Slater integrals are used to calculate the energy of multi-electron systems, but the specific equations and methods may vary depending on the level of your course and the specific problem you are trying to solve. Good luck with your studies!
 

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