Finding the gravitational force

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SUMMARY

The discussion focuses on calculating the gravitational force acting on mass 1, given that each mass is 2 kg. The user attempts to apply the formula F=F12+F13, indicating a need for vector addition to determine the net gravitational force. The configuration of the masses suggests the use of superposition principles, particularly in scenarios involving equilateral triangles where certain force components may cancel out. The hypotenuse calculation of √29 is also mentioned, which is relevant for determining distances in the force equations.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with vector addition in physics
  • Knowledge of basic trigonometry for resolving forces
  • Ability to interpret geometric configurations in physics problems
NEXT STEPS
  • Study Newton's Law of Universal Gravitation and its applications
  • Learn about vector resolution and force components in physics
  • Explore the concept of superposition in force calculations
  • Practice problems involving gravitational forces in triangular configurations
USEFUL FOR

Students preparing for physics exams, particularly those focusing on gravitational forces and vector analysis. This discussion is beneficial for anyone needing to solidify their understanding of gravitational interactions and force calculations in various configurations.

nissanfreak
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This is the last question I have on my study guide that I can't solve. My physics test is tomorrow and I just want to be ready for it. Please help me figure this one out!

What is the gravitation force on mass 1 if each mass is 2 kg?

O<---(5m)---->O mass3
I -
I -
(2m) -
I -
O - < mass1

Well I hope you can understand that.
I know that the hypotonuse is the square root of 29 so I am guessing I need to use the formula F=F12+F13 to get the answer right or wrong?
 
Last edited:
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well my crude attempt at a diagram didnt come out so good lol. But its supposed to look like a triangle.
 
If you're trying to use the net force, then you will want to use superposition, which is basically what you are implementing. If its an equilateral triangle then some components will cancel, depending on how the triangle is configured.
 

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