Stuck on vector integral, Calc III log_2

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SUMMARY

The discussion centers on solving the integral of the logarithm base 2, specifically the expression \(\int \log_2 t \, dt\). The user successfully converts the logarithm to natural logarithm using the formula \(\log_2 t = \frac{\ln t}{\ln 2}\). This leads to the integral being expressed as \(\frac{1}{\ln 2} \int \ln t \, dt\). The solution involves applying integration by parts, where \(f = \ln t\) and \(dg = dt\).

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mr_coffee
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Hello everyone I'm stuck on this problem its an integral but i don't know how to integrate the log_2 part, i converted it to natural log:
Here is what I have:
http://img278.imageshack.us/img278/1158/integral9lo.jpg
Thanks.
 
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As you say

[tex]\log _2 t = \frac{{\ln t}}{{\ln 2}}[/tex]

So

[tex]\int {\log _2 tdt = } \int {\frac{{\ln t}}{{\ln 2}}} dt = \frac{1}{{\ln 2}}\int {\ln tdt}[/tex]

So now it's just integrating ln(t)dt. If you don't remember how, think integration by parts with f = lnt and dg = dt.
 

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