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Finding the shear centre of a nonhomogeneous cross section cross 
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#1
May1810, 09:39 AM

#2
May1810, 11:47 PM

P: 699

your line: "shearing stress=LaTeX Code: \\int LaTeX Code: \\int (V*Q/I/b)da*2.15 where 2.15 is the distance between the horizontal forces"
comment: I'm not sure what all those integral signs are doing. I thought shearing stress was just V*Q/I/b. (That is, the result of integration). OK, so you multiply by area to get force, and then by 2.15 to obtain moment. So should your "shearing stress" read as "moment"? 


#3
May1910, 12:46 PM

P: 591

o yes, thats correct, meant to be moment, but it still wont change the answer,
im beginning to think that the way i expanded the cross section was incorrect, i just made the 2 horizontals 30 times longer ( to the right) maybe i was meant to expand them to both sides, 14.5 to each side, doing this would still not give me a correct answer, but much closer, by doing this i get 0.49cm is it possible that the answer i was given in the textbook (0.408) is incorrect, could someone please check this for me 


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