|Nov12-12, 11:52 AM||#1|
How may I plot the trajectory of a particle whose movement vectors are given as:
x(t) = Rwt - Rsin(wt)
y(t) = R - Rcos(wt)
I have tried squaring both x and y and adding them, to infer some sort of circular trajectory, to no avail. Could someone please assist/make a suggestion?
|Nov12-12, 12:00 PM||#2|
You didn't mention in what plotting program (matlab,scilab, gnuplot) but usually, you need to create a vector of values for time first, then calculate the x and y vectors and plot y against x.
e.g. in matlab and scilab you do:
|Nov12-12, 12:01 PM||#3|
I am not supposed to use any program, simply infer the general scheme of the trajectory from the equations. Any ideas?
|Nov12-12, 12:36 PM||#4|
OK, then do this:
start from t=0 to get the starting point (x,y).
Then, knowing that (x,y)=(-Rsin(t),-Rcos(t)) describes a circle of radius R, what will happen if every y-value is moved up by R? You simply translate your circle.
Then, what happens if every x-value is moved right by Rt? It will not be a circle anymore. For instance, the end-point at t=2*pi (when w=1) will have moved to x=R*2*pi. You can take one or two other t-values to get the shape.
I have taken w=1, but it is easy to generalize the above approach.
|Nov12-12, 02:16 PM||#5|
Supposing now that the particle's trajectory is given by at^2+bt, where units of a are m/s^2 and units of b are m/s. How am I to calculate its tangential and centripetal accelerations? I know that the radial acceleration is equal to r*w^2 but what about the tangential acceleration and how is all of that related to the trajectory as given with parameters a and b? Do I simply differentiate twice wrt t?
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