## Maxwell Lagrangian

Hello,

Where can I find a good explanation (book) of the derivation via Noether's theorem of the three momentum and angular momentum operators of the usual maxwell lagrangian ?

Thank you!

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 Blog Entries: 9 Recognitions: Homework Help Science Advisor This is standard QFT (actually QED) material, any thorough book should have it. Check out a nice treatment in Chapter 2 of F. Gross' "Relativistic Quantum Mechanics and Field Theory", Wiley, 1999. In purely classical context (no operators), advanced electrodynamics books should also have this.

 Quote by dextercioby This is standard QFT (actually QED) material, any thorough book should have it. Check out a nice treatment in Chapter 2 of F. Gross' "Relativistic Quantum Mechanics and Field Theory", Wiley, 1999. In purely classical context (no operators), advanced electrodynamics books should also have this.
I've been watching the book and yes, the book treats it but don't deduce them. He just announces and perform some calculations with them

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## Maxwell Lagrangian

Can you calculate $T^{\mu\nu}$ and $M^{\lambda}_{~~\mu\nu}$ from the Lagrangian and the general Noether formula which for the energy-momentum 4 tensor reads:

$T^{\mu}_{~~\nu}$ = ($\frac{\partial \mathcal{L}}{\partial(\partial_{\mu}A_{\rho})}$ $-\mathcal{L}\delta^{\mu}_{\lambda}$) X $\frac{\partial x'^{\lambda}}{\partial\epsilon^{\nu}}$,

where

$$x'^{\mu} = x^{\mu} + \epsilon^{\mu}$$

 Quote by dextercioby Can you calculate $T^{\mu\nu}$ and $M^{\lambda}_{~~\mu\nu}$ from the Lagrangian and the general Noether formula which for the energy-momentum 4 tensor reads: $T^{\mu}_{~~\nu}$ = ($\frac{\partial \mathcal{L}}{\partial(\partial_{\mu}A_{\rho})}$ $-\mathcal{L}\delta^{\mu}_{\lambda}$) X $\frac{\partial x'^{\lambda}}{\partial\epsilon^{\nu}}$, where $$x'^{\mu} = x^{\mu} + \epsilon^{\mu}$$
I'll try it.

 Quote by dextercioby Can you calculate $T^{\mu\nu}$ and $M^{\lambda}_{~~\mu\nu}$ from the Lagrangian and the general Noether formula which for the energy-momentum 4 tensor reads: $T^{\mu}_{~~\nu}$ = ($\frac{\partial \mathcal{L}}{\partial(\partial_{\mu}A_{\rho})}$ $-\mathcal{L}\delta^{\mu}_{\lambda}$) X $\frac{\partial x'^{\lambda}}{\partial\epsilon^{\nu}}$, where $$x'^{\mu} = x^{\mu} + \epsilon^{\mu}$$
$$T^{\mu\nu}=-F^{\mu\nu}\partial^{\nu}A_{\rho}+\frac{1}{4}F^{2}g^{\mu\nu}$$

And now? How I relate this to the momentum and total angular momentum operators ?

 Blog Entries: 9 Recognitions: Homework Help Science Advisor The momentum should be $T^{0i}$, just like energy is $T^{00}$. For angular momentum, you should derive the general formula using the linearized version of a general Lorentz transformation (i.e. a linearized space-time rotation): x'μ=xμ+ϵμ ν xν, where ϵμν = - ϵνμ A minor change Tμν=−Fμρ∂νAρ+1/4 F2gμν

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