# How to integrate ln(x)

by ekinnike
Tags: integrate
 HW Helper P: 1,422 Integration is a Calculus topic, and therefore, should not be posted in the Precalculus section. Anyway, to integrate ln(x), we use Integration by Parts (have you covered Integration by Parts yet?), i.e: $$\int u dv = uv - \int v du$$ We often use Integration by Parts, when no other methods can solve the integral. So, we want to integrate this: $$\int \ln (x) dx$$ We then let u = ln(x), and dv = dx So that implies du = dx / x, and v = x. Substitute all those into the formula, we have: $$\int \ln (x) dx = x \ln (x) - \int x \times \frac{dx}{x} = ...$$ Can you go from here? :)
 Quote by VietDao29 Integration is a Calculus topic, and therefore, should not be posted in the Precalculus section. Anyway, to integrate ln(x), we use Integration by Parts (have you covered Integration by Parts yet?), i.e: $$\int u dv = uv - \int v du$$ We often use Integration by Parts, when no other methods can solve the integral. So, we want to integrate this: $$\int \ln (x) dx$$ We then let u = ln(x), and dv = dx So that implies du = dx / x, and v = x. Substitute all those into the formula, we have: $$\int \ln (x) dx = x \ln (x) - \int x \times \frac{dx}{x} = ...$$ Can you go from here? :)