|May26-07, 03:35 PM||#1|
Atomic mass and mass excess
1. The problem statement, all variables and given/known data
In Clark's tables, the atomic masses of various isotopes are given which are decimal form. Are these experimentally obtained masses? Moreover, while writing nuclear reactions we do not use these, instead they are represented as integers. Is it just for convenience or is there any particular reason for this?In Schaums book on Modern Physics, they have defined the difference between the 2 masses as mass excess.Could somebody please explain the relation between these 2 values?
2. Relevant equations
3. The attempt at a solution
|May26-07, 04:05 PM||#2|
I think the nuclear reactions round to the nearest integer, or sometimes use the types of isotopes used in your profession (like physics for the health sciences might deal with molybdenum-xx into technetium-99, since radiologists use this to help make detections in living systems).
The excess mass has something to do with the energy that is released (and absorbed for fusion? not sure...) in the fission reactions.
Remember how Einstein equated mass to energy? In Nuclear physics, you get to actually see how that works...
|Similar Threads for: Atomic mass and mass excess|
|atomic mass vs. atomic number||Introductory Physics Homework||9|
|atomic mass unit||Introductory Physics Homework||7|
|Help with problem of Center of mass, linear mass density and total mass||Introductory Physics Homework||1|
|The Atomic Mass!!||Chemistry||2|
|Atomic Mass Units||Introductory Physics Homework||3|