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ZedCar
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Homework Statement
The uranium isotope 235U captures a neutron and undergoes fission to produce 93Rb and 141Cs. Calculate the energy released in this process.
The nuclear masses of the relevant isotopes are
235U 235.0439u,
93Rb 92.9217u,
141Cs 140.9195u
Homework Equations
The Attempt at a Solution
The answer is given as
n + 235U → 93Rb + 141Cs + 2n
LHS 235.0439 + 1.0087
RHS 92.921712 + 140.91949 + 2.10087
Difference is 0.1943u = 181 MeV
I realize the quantity of 1.0087 is the mass of neutron divided by one unified atomic mass unit. So that's (1.67493 x 10^-27) / (1.66 x 10^-27).
Also, the 2.10087 number is simply double this.
How have the 235.0439, 92.921712 & 140.91949 values been calculated? I know it's to do with E=Mc^2
Thank you.