
#1
Mar1408, 04:37 PM

P: 147

I'm trying to deal a problem using this formula, but I'm unclear as to what dl represents (Or if it is the same as dx in most integrals, then in that case I don't know what the lowercase L is)
[tex]{\cal{E}} = \int_{a}^{b} \vec{E} \cdot \vec{dl}[/tex] 



#2
Mar1408, 04:56 PM

Sci Advisor
HW Helper
Thanks
P: 25,167

Along a general curve l(t)=(x(t),y(t)), dl=(x'(t)*dt,y'(t)*dt). So if E=(Ex,Ey) that becomes Ex*x'(t)*dt+Ey*y'(t)*dt.



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