## planet is 2.00 a.u. when closest to sun. eccentricty is .500. find period

1. The problem statement, all variables and given/known data

a planet is 2.00 a.u. when it is closest to the sun. its eccentricity is .5000. Find its period in years.

2. Relevant equations

3. The attempt at a solution

i got this so far... don't know if it is right

-AD - PD = F <SUBTRACTING THESE TWO>

2PD = A - F
2PD = A - (EA)
2PD = A(1-E)
2PD/(1-E) = A

A = 2(2)/(1.-.5)
A= 8 a.u.

then for a

a= 8.00/2
a= 4.00 a.u.

T^2 = a^3

T = sqrt(a^3)
T = 8

im lost T = 8 what? years?

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 kepler's 3rd law says Period( in years) is directly proportional to semi axis (a) cubed. correct? so was that last line: T^2 = a^3 correct?
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## planet is 2.00 a.u. when closest to sun. eccentricty is .500. find period

anyone i got a 7 15 dead line