What is the period of the second planet in this exercise?

In summary, the problem involves two planets orbiting the same sun in a distant galaxy. The first planet has a distance of m and a period of 108 s. Using the equation T^2=constant * r^3, the constant is calculated to be 2*10^-33. However, when using this constant to calculate the period of the second planet with a distance of m, the result is 38.18 s which does not match any of the given options. It is concluded that the period in the problem should be 10^8 s instead of 108 s.
  • #1
OierL
5
0

Homework Statement


In a distant galaxy, a planet orbits its sun at a distance of
c28fb096237b0a04a15c64e37a292086.gif
m with a period of 108 s. A second planet orbits the same sun at a distance of
6b8c23b8fdf999e3d16717c8daf58b5e.gif
m. What is the period of the second planet?

Select one:
a.
55c2bc2f030e754241487b390145364b.gif
s
b.
b1558216fac73da8cf7be349fc9c0524.gif
s
c.
aaaf30018536b0436cdd4a744f488597.gif
s
d.
605809b649a0376f8fa4b8c28d33f15f.gif
s
e.
6f428d14e6b8e2ae0744043ee5d58576.gif


Homework Equations


T^2=constant * r^3

The Attempt at a Solution


First of all I compute the constant whit the values of the first planet:
(108)^2 = const. * (1'8*10^12)^3 → const= 2*10^-33
Then, I compute the period of the second planet:
T^2 = 2*10^-33 * (9*10^11)^3 → T = √1458 = 38,18 s
This solution doesn't apear in the results I have to choose. What do I have wrong?

Thank you!
 

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  • #2
I suspect the period in the problem should read [itex] 10^8 [/itex]s, not 108 s. 108s is an unphysical orbital period for a planet at this distance.
 
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Likes Buzz Bloom and OierL
  • #3
phyzguy said:
I suspect the period in the problem should read [itex] 10^8 [/itex]s, not 108 s. 108s is an unphysical orbital period for a planet at this distance.
You are right! If I do the exercise with [itex] 10^8 [/itex]s the result coincides with e.
Thank you very much!
 

1. What is the second planet in this exercise?

The second planet in this exercise refers to the second planet in the solar system, which is Venus. It is the second closest planet to the sun and is known for its hot and toxic atmosphere.

2. How is the period of a planet determined?

The period of a planet is determined by its orbital period, which is the time it takes for the planet to complete one full orbit around the sun. This can be calculated by using the planet's distance from the sun and its orbital speed.

3. What is the period of Venus?

The period of Venus is approximately 225 Earth days. This means that it takes Venus 225 days to complete one full orbit around the sun.

4. How does the period of Venus compare to other planets in the solar system?

Venus has the longest period of all the terrestrial planets (Mercury, Venus, Earth, and Mars) in the solar system. It is also the second longest overall, with only the gas giant planets having longer periods.

5. Why is the period of Venus important to study?

The period of Venus is important to study because it provides insight into the planet's rotation and orbit, which can help us understand its climate, geology, and potential for life. It also allows us to make comparisons with other planets and better understand our solar system as a whole.

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