
#1
Jul1808, 08:23 AM

P: 3

i hv a question....???
plis help me!!! a vertical container with base area measuring 14 cm by 17 cm is being filled with identical pieces of candy, each with a volume of 50 mm^3 and mass of 0.02 gr. assume that the volume of the empty spaces between the candis is negligible. if the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kilograms per minute) does the mass of the candies in the container increases? 



#2
Jul1808, 10:46 AM

HW Helper
P: 5,346

What have you done? What formulas do you think apply? How have you tried to solve it other than post it here hoping perhaps someone would do it for you? 



#3
Jul1908, 07:04 AM

P: 3

yes i get already.... dm/dt=dm/dh x dh/dt
thx.. of ur help 



#4
Jul1908, 09:23 AM

HW Helper
P: 5,346

measuringYou are given mass per volume. You are told the rate of change in height. Any ideas about how to figure the rate of change in volume? 



#5
Aug2308, 05:23 PM

P: 5





#6
Aug2308, 05:48 PM

P: 5

Nevermind haha I related the rate of volume to the given candy density and found the rate of candy mass change! Thanks anyway :D




#7
Aug2308, 06:47 PM

HW Helper
P: 5,346

"each with a volume of 50 mm^3 and mass of 0.02 gr" I trust this was the density that you used times the increase in volume to establish your mass rate of change. I'm glad you apparently have a handle on it. 


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