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AC circuit, mystery impedance 
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#1
Oct408, 11:05 AM

#2
Oct408, 02:31 PM

P: 778

You have apparently chosen the first positive peak of V1 for its phase, but for the phase of V2 you have chosen the first positive going zero crossing. You have to be consistent in these choices.
Looking at the zero crossings of V1, the angle appears to be closer to 45 degrees than 48 degrees. Since the positive going zero crossing of V1 nearest to the zero time of the graph is at 45 degrees, I would say that V1 = 10sqrt(2)<45, and then it would be consistent to say that V2 = 5/sqrt(2)<0. Redo your calculations with this number for V1 and see if you get better results. 


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