Altitude Adjustments for Pressure Cookers: Why is it Necessary?

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Discussion Overview

The discussion centers on the necessity of adjusting pressure or cooking times for pressure cookers (autoclaves) at high altitudes, exploring the relationship between external air pressure and internal pressure within the cooker. Participants examine the implications of altitude on cooking processes, particularly in terms of temperature and pressure dynamics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question whether the weight regulating the pressure inside the cooker remains effective at higher altitudes due to reduced external air pressure.
  • There is a suggestion that the difference in external pressure at sea level and at 5000 feet could lead to a corresponding difference in internal pressure, potentially affecting cooking outcomes.
  • One participant proposes that the internal pressure of a pressure cooker at high altitude would be lower than at sea level due to the lower external pressure, despite the weight remaining constant.
  • Another participant mentions that the absolute pressure inside the cooker changes with altitude, leading to the need for adjustments in cooking times or pressures.
  • Some participants note that the lower external pressure allows the valve to release steam more frequently, which could influence heat retention and cooking efficiency.

Areas of Agreement / Disagreement

Participants express differing views on how altitude affects pressure cookers, with no consensus reached on the exact implications of external pressure changes on internal pressure and cooking times.

Contextual Notes

Participants reference the relationship between internal and external pressures but do not provide a definitive calculation method for determining the impact of altitude on pressure cooker performance. The discussion remains open to interpretation and further exploration.

Who May Find This Useful

This discussion may be of interest to individuals involved in cooking, food science, or those curious about the physics of pressure and temperature in relation to altitude.

ntdmods
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When operating a pressure cooker (autoclave) at high altitudes, why is it necessary to adjust pressure or cooking times to maintain the target temperature ? The weight of the ball that holds in pressure is still the same, therefore temperature and pressure should be the same. At 15psi the temperature should be 121°C at sea level or at 5000 feet. Since the weight that is keeping in pressure is always constant, the pressure inside the vessel should also remain constant. But, altitude adjustments are usually recommended. Is the reduction of air pressure at higher altitudes enough to affect the weight?


Edit: Let me see if I can explain the problem a bit better...
Air pressure at sea level is roughly 14.7psi. Air pressure at 5000ft is roughly 12.2psi. Would this difference in pressure have any significant effect on the internal pressure of the vessel by acting upon the weight used to regulate the pressure? Basically there is roughly 2.5psi difference between the altitudes. Would this correspond to a 2.5psi difference in the internal pressure of the vessel? I.E.- it would only reach a maximum of 12.5psi at 5000ft instead of 15psi at sea level?

It makes sense to me that if I were to take a pressure cooker at sea level pressure (cooking at 15psi) and reduce the external pressure to that at 5000ft, the weight regulating internal pressure would be more easily displaced. Thus, steam would vent violently from the sudden change in external pressure.

I don't know which way to go on this. Since the weight is constant, I would think that the pressure would also remain constant. But then again, if the outside pressure is lower, it seems as though there would be less force acting upon the weight, therefore allowing it to vent internal pressure at a lower external pressure.

If so, would this loss in external pressure acting upon the weight be enough to alter internal pressure significantly? Is there any way I can calculate the difference? Is the difference in direct relation to the external pressure (I.E. - a 2psi difference in external pressure would result in a 2psi loss of internal pressure)?
 
Last edited:
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ntdmods said:
When operating a pressure cooker (autoclave) at high altitudes, why is it necessary to adjust pressure or cooking times to maintain the target temperature ? The weight of the ball that holds in pressure is still the same, therefore temperature and pressure should be the same. At 15psi the temperature should be 121°C at sea level or at 5000 feet. Since the weight that is keeping in pressure is always constant, the pressure inside the vessel should also remain constant. But, altitude adjustments are usually recommended. Is the reduction of air pressure at higher altitudes enough to affect the weight?


Edit: Let me see if I can explain the problem a bit better...
Air pressure at sea level is roughly 14.7psi. Air pressure at 5000ft is roughly 12.2psi. Would this difference in pressure have any significant effect on the internal pressure of the vessel by acting upon the weight used to regulate the pressure? Basically there is roughly 2.5psi difference between the altitudes. Would this correspond to a 2.5psi difference in the internal pressure of the vessel? I.E.- it would only reach a maximum of 12.5psi at 5000ft instead of 15psi at sea level?

It makes sense to me that if I were to take a pressure cooker at sea level pressure (cooking at 15psi) and reduce the external pressure to that at 5000ft, the weight regulating internal pressure would be more easily displaced. Thus, steam would vent violently from the sudden change in external pressure.

I don't know which way to go on this. Since the weight is constant, I would think that the pressure would also remain constant. But then again, if the outside pressure is lower, it seems as though there would be less force acting upon the weight, therefore allowing it to vent internal pressure at a lower external pressure.

If so, would this loss in external pressure acting upon the weight be enough to alter internal pressure significantly? Is there any way I can calculate the difference? Is the difference in direct relation to the external pressure (I.E. - a 2psi difference in external pressure would result in a 2psi loss of internal pressure)?

Believe it or not there exist websites with info on this! I googled on "Pressure Cooker" and "altitude" and got this:
http://missvickie.com/library/altitude.html
(I wonder if that is Tiny Tim's "miss vickie"?)

Basically, the point is that the pressure cooker controls ITS pressure in reference to the outside pressure. If you are using a pressure cooker at high altitude, the pressure cooker sets its internal pressure PROPORTIONAL TO the outside air pressure which is slightly lower than at sea level.
 
Last edited by a moderator:
Ok...

First, I have googled previously on this subject, and indeed found the link you provided. I have not found a website that explains why this happens though, which is why I posted here.


I think I understand the concept now after sleeping on it. For example:
A pressure cooker operating at sea level with a 15psi internal pressure will actually have a 29.7psi absolute pressure. At 5000ft altitude, the outside air pressure is only 12.2psi, therefore the internal absolute pressure would only be 27.7psi. The weight still maintains 15psi internal pressure, but since the outside pressure has been reduced, the absolute pressure is also reduced. Thus the need for increased cooking times or increased pressures (just if anyone is curious, this is not for cooking but sterilization of media).

Am I correct?
 
The lower pressure of the air let's the valve blow off steam more frequently and as a result heat is released more frequently.
 
GOD__AM said:
The lower pressure of the air let's the valve blow off steam more frequently and as a result heat is released more frequently.

...Because the amount of pressure pushing on the weight is calculated by the difference between internal and external pressures?
 

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