Value of the constant in 'variation of refractive index'


by Donchay
Tags: glass, optics, refractive index
Donchay
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#1
Mar17-13, 09:52 PM
P: 10
In optics, given the below formula

nλ= A + B/λ2 + C/λ4 +......

where A, B and C are constants.

From the above relationship we can deduce that as the wavelength λ increases, the variation of refractive index nλ decreases.

How do we measure the constant value of A,B and C at the first place?
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DrDu
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#2
Mar18-13, 02:42 AM
Sci Advisor
P: 3,359
You measure the refractive index at several wavelengths and then you fit the formula to the values obtained.
Donchay
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#3
Mar29-13, 04:30 AM
P: 10
Thank You DrDu.
While the above formula is for Optical Dispersion, then is it the same dispersion for the Abbe Number:

Vd=(nD-1)/nF-nC

where nF-nC is the dispersion according to this link http://glassproperties.com/abbe_number/

but somehow on other link I read that nF-nC is called Principal Dispersion. I try to search on more about Principal Dispersion but there is almost none explanation about it.

DrDu
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#4
Mar29-13, 05:30 AM
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P: 3,359

Value of the constant in 'variation of refractive index'


n_F is the index of refraction for blue light while n_C is for red light (see the table with the line frequencies).
One assumes that for glass the dispersion is approximately linear over the optical frequency range.
Donchay
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#5
Mar29-13, 08:27 AM
P: 10
I understand about the line frequencies. Just that is it n(lambda)=n_F - n_C ?
DrDu
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#6
Mar29-13, 09:27 AM
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I would try something like ## n(\lambda)=n_C+(n_F-n_C)\frac{1/\lambda_C^2-1/\lambda^2}{1/\lambda_C^2-1/\lambda_F^2} ##.


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