Recent content by AdiV
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Cylindrical Rotation Volume Help
Ohh, thanks, yeah I made a calculation error, Thanks!- AdiV
- Post #3
- Forum: Calculus and Beyond Homework Help
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Cylindrical Rotation Volume Help
Homework Statement The region R enclosed by the coordinate axes and the graph of y = k(x-2)^2 is shown above. When this region is revolved around the y - axis, the solid formed has a volume of 8*pi cubic units. What is the value of k? A) 1 B) 4/3 C) 3/pi D) 2 E) 3 Homework...- AdiV
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- Cylindrical Rotation Volume
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Need Help With Guass Laws and Amperes Law
Wow, thank you so much!- AdiV
- Post #12
- Forum: Introductory Physics Homework Help
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Need Help With Guass Laws and Amperes Law
The E field in a conductor is zero right?- AdiV
- Post #10
- Forum: Introductory Physics Homework Help
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Need Help With Guass Laws and Amperes Law
Ohh, ok, I think I understand now, so for region II the charge would be -2q since that is the charge of the conductor- AdiV
- Post #8
- Forum: Introductory Physics Homework Help
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Need Help With Guass Laws and Amperes Law
The charge on the conductor is -2q, so +q + -2q will be -q so that is the charge in region I?- AdiV
- Post #6
- Forum: Introductory Physics Homework Help
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Need Help With Guass Laws and Amperes Law
The total charge is + q? Can we go over this a bit more? I am really feeling lost right now.- AdiV
- Post #4
- Forum: Introductory Physics Homework Help
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Need Help With Guass Laws and Amperes Law
Ok, I 've been working on it and well, I got to this point, but am not too sure. a) sigma E perpendicular delta A = E * sigma delta A = E(4*pi*r^2) = Q / epsilon So wouldn't the charge in section I be +q / epsilon? c) sigma E perpendicular to delta A = E * sigma A = E * (4 pi r^2) = Q...- AdiV
- Post #2
- Forum: Introductory Physics Homework Help
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Need Help With Guass Laws and Amperes Law
Hi, I am really stuck with these problems, is it possible you guys can help me out, by guiding me along this problem, I wil write the entire thing out, but would appreciate it if you guys help me step by step so that I can understand it, since I am having a VERY hard time with these problems...- AdiV
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- Amperes law Law Laws
- Replies: 12
- Forum: Introductory Physics Homework Help
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Finding Inflection Points: Solving for a,b, and c
Ohh, ok, yes, I fixed it now, I have my answer to be a = -6 b = 9 c = 1- AdiV
- Post #5
- Forum: Calculus and Beyond Homework Help
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Finding Inflection Points: Solving for a,b, and c
Yep, thanks I figured it out a = -9/2 b = 11 But I can't find out what c is; This is wat I did by the way; y = x3 + ax2 + bx + c y' = 3x2 + 2ax + b y'' = 6x + 2a Take y' and plug in (1, 5) 5 = 3(1) + 2a(1) + b ==> 2a + b = 2 ... (1) Take y'' and plug in (2...- AdiV
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding Inflection Points: Solving for a,b, and c
Hi, can someone help me guide me on how to find inflections? I am not too sure how to do it in such a problem as the follows: Homework Statement Determine a, b, and c so that the function f(x) = x^3 + ax^2 + bx + c has critical points at (1,5) and an inflection point at (2,3)...- AdiV
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- Points
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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How Do You Solve Second Derivatives Using Implicit Differentiation?
Wow, thanks for clearing it up for me, I greatly appreciate the help =]- AdiV
- Post #7
- Forum: Calculus and Beyond Homework Help
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How Do You Solve Second Derivatives Using Implicit Differentiation?
Ohh, so go through the process again? Ok, but can you help me along?- AdiV
- Post #3
- Forum: Calculus and Beyond Homework Help
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How Do You Solve Second Derivatives Using Implicit Differentiation?
Hi, I need some help with these question, and would appreciate the help. Homework Statement Part 1 Use implicit differentiation to find y'' if 2xy = y^2 Simplify and Leaev in terms of x and y. Part 2 Use implicit differentiation to find y '' if xy + y^3 = 1 Simplify your answer and...- AdiV
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- Differentiation Implicit Implicit differentiation
- Replies: 6
- Forum: Calculus and Beyond Homework Help