Recent content by AdsBerger

well that somewhere in my calculations i am wrong. redid it to get 9.2x10^-4 which when plugged into the site is correct

i entered my .9m and 5 A to get a B of 0.000003399992 what does this tell me ?

i actually tried using that but not to sure on all of its function, as soon as i enter 5 A it calculates everything

redid the first line got the new answer of 6.28x10^-6 not sure of my miscaculation. this resulted in the new answer of .924m seems more plausible.

i found a value for it.. 4∏ x10^-7 but the rest of the question goes like this then = (3.14x10^-6)/2r = 1.57 x 10^-6/r 3.4 x 10^-3 = 1.57 x 10^-6/r 1.57 x 10^-6 = 3.4 x 10^-3 r 4.62x10^-4 = r 0.0004617647059 m this doesn't seem right

Homework Statement A current of 5 A is passed through a single wire loop, producing a magnetic field of 3.4 x 10^-3 T at the center. What is the radius of the loop? Homework Equations B = μNi / 2r The Attempt at a Solution B = 3.4 x 10^-3 N = 1 i = 5 B = μNi / 2r 3.4 x...

The angle beta would be 50. i calculated his velocity to be 10.85 m/s

I am thinking i will have to use the equation v = √{2gL[1-cos(a)]} v = √{2(9.8)(12) [1-cos(a)]} What would the angle be though?

Homework Statement A man standing on a 15 m high cliff tries to swing on a 12 m rope and let's go at 30° of the horizontal (travelling 150°). He let's go and travels through the air, to then land on the ground. What is his distance from his landing spot to the base of the cliff...

Homework Statement A man is trying to swing from a 15 m high cliff on a 12 m long rope. (the rope is horizontal at the start) He let's go when the rope is 30° degrees from the horizontal of the other side. (totaled swung angle is 150°. How far does he go from the cliff? Homework...

I believe i ended up getting it. answer 600m

So the initial speed no matter the angle you fire at will all be the same?

Homework Statement A launcher fires a ball that weighs 30kg straight up to a height of 300m. What is the maximum range of the ball could be fired at? Homework Equations V^2 = V^2-2(a)(d) R = ( V02 Sin2θ ) / gThe Attempt at a Solution To find the maximum range i know that it has to be...