Thank you twofish-quant :smile:
When you just started a PhD where you aware of your possibilities after finishing it outside academia?
Also since you did a lot of programming your experience might be easily transferred elsewhere, is that correct? I mean even outside the realm of physics.
Greetings
I have a dilemma, hopefully some of you can help. And yes I did research a lot about this on google but I think a new discussion is more helpful.
Where did you get your PhD in? Was it worth it? What are the options outside academia?
I have an opportunity to get a PhD position...
Greetings
Next semester I'll have solid state physics, statistical physics and and introductionary course in elementary particles. So I was wondering maby those of you who had those subjects could recommend me some books.
I really liked books by Griffiths so far. Especially the one on...
So what you are saying is that I can already write the operator within the "average" brackets like this
< \hat{Q} >
?
I thought I was not allowed to do that and had to write
< Q >
instead and only once I am trying to compute the expectation value I...
Cool, I like this kind of approach :)
Well, I think it would look like this, right?
\sigma^{2}_{H}=\langle(H-{\langle}H{\rangle})^2\rangle=\langle\psi\mid(\hat {H}-{\langle}H{\rangle})^2\psi\rangle
Notice I didn't write the hat on H in the second expression ( the part I don't...
This I know
Is there a difference? I think there is none. Feel free to correct me
Let me clarify. First of all I don't understand why in this expression
\sigma^{2}_{Q}=\langle(\hat{Q}-{\langle}Q{\rangle})^2\rangle
we use the operator Q instead of the value Q.
For example if we make repeated...
There are two things I don't understand here:
Firstly, why in the standard deviation expression we use the Q operator instead of the Q value itself? Writting Q seemed more natural and then in the next expression I would just stick the corresponding operator. Which would lead to the same result...