What is the largest wavelength for emission of electrons from a photosurface?

Click For Summary
SUMMARY

The largest wavelength for the emission of electrons from a photosurface can be calculated using the photoelectric effect principles. When light of wavelength 2.08 x 10-7 m is used, a stopping voltage of 1.40V indicates the work function of the photosurface. The relationship between the wavelength of incident light and the energy of emitted electrons is defined by the equation Energy = h * speed / wavelength, where h is Planck's constant. This discussion emphasizes the need to understand the work function to determine the maximum wavelength for electron emission.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with Planck's constant (h)
  • Knowledge of voltage and energy relationships
  • Basic concepts of wavelength and frequency
NEXT STEPS
  • Research the calculation of work function using stopping voltage
  • Learn about the photoelectric effect and its applications
  • Explore the relationship between frequency and wavelength in electromagnetic radiation
  • Study the implications of electron emission in various materials
USEFUL FOR

Physicists, students studying quantum mechanics, and anyone interested in the principles of the photoelectric effect and electron emission from materials.

prakriti
Messages
2
Reaction score
0
1) when light of wavelength 2.08*10^-7m falls on a photosurface, a voltage of 1.40V is required to stop the emitted electrons from reaching the anode. What is the largest wavelength of light that will result in emission of electrons from this photosurface?


2) To determine the work function of given photosurface, light of wavelength 2.3*10^-7 m is directed at the surface and the stopping voltage is recorded. When light of wavelength 1.8*10^-7m large as the previous one. Find the work function.
 
Last edited:
Physics news on Phys.org
What is the relationship between the wavelength of the incident light and the energy of the emitted electrons?
 
isnt it f = speed / wavelength
and Energy = h*f
so Energy = h*speed/wavelength
but i just can't figure out the problem.. please help!
 
look up the photoelectric effect
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
14K
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K