Recent content by blizzardof96

Hi All, I'm looking for an analytical solution to the open channel rectangular fluid flow profile. The flow is bounded by three walls but the top is open to atmosphere. Assume steady state flow that is parallel and incompressible.I've already found information involving a rectangular flow...

Thank you. This is helpful. The other alternative is to assume that (1/Rtot) is slope "m" if you plot H vs Q with H along the x axis.

Thank you very kindly. This is what I have so far. Rtotal = ∑Ri = 3R ("resistors in series") Q without any resistance is 9.5 x 10^-6 m^3/s Height (cm) = [13.5 27 40.5 54 67.5 81 94.5 108 121.5 135 148.5 162 175.5] Flow Rate given 3R (mL/s) = [0.007 0.008 0.009 0.012 0.018 0.025 0.033 0.042...

I assume this should be treated like a circuit in series.

Imagine you have a vertical pressure head 2m tall with water flowing down to height 0m and emptying. Through this length we have 3 identical tubes of resistance R and length L. Assuming I know the volumetric flow rate(Q) as a function of height, how can I calculate the resistance of each tube...

Okay, that is interesting. Assuming we place the detector at a position before the focal point and spherical aberration is essentially negligible(as you mentioned), would the intensity of the light on the detector(from different rays) be inversely proportional to path length within the solid sphere?

You are correct about the focal length. I calculated it to be 68R suggesting a weaker focusing action. Can you explain why you believe that rays near the centre are delayed relative to the edge?

Assume you have the following scenario: Light begins traveling through a gel of index of refraction n=1.34 in a straight line along the x axis. It is then incident on a solid sphere(n=1.36) of radius R in 3-space. Upon transmittance, the light again travels through the gel(n=1.36) and finally...

Thank you. As a third year undergrad with less physics knowledge than yourself I appreciate it.

I have doubts as the value for Vtotal seems unnecessarily complex and there is nothing in the final expression that can simplify. The solution appears much different from the usual form we see in an electric potential problem.

Homework Statement The z = 0 plane is a grounded conducting surface. A point charge q is at (0,0,a), and charge 4q at (0,-2a,a). Calculate the potential in the region z > 0. Homework Equations V=∑kq/rThe Attempt at a Solution [/B] Use the method of images. V1 = kq/r+ + kq/r- V1=kq(1/sqrt(x^2...

Homework Statement An object is 25.0 cm to the left of a lens with a focal length of + 15 .0 cm. A second lens of focal length +15.0 cm is 30.0 cm to the right of the first lens. Find the location of the final image and draw it out. Homework Equations 1/f = 1/di + 1/do The Attempt at a...

Lets assume: emissivity of a human=0.91 T=310K Surface area body: 1.60 m^2 If we use the Stefan-Boltzmann Law we can find a value for the rate of emission of light by a human. Rate emission=762 J/s Given this rate of emission, why don't humans glow in the dark?

So we can conclude that its infinite at r=0? Thank you for clarifying.

That makes sense. Can we then say that the charge density and therefore the divergence is finite at the origin(and equal to 4pi)?