Recent content by califauna

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    How is V1 deduced to be zero in the last step here?

    Not sure if the glitch in the matrix type clue about the balls passing through each other is a hint at this particlar law, but, Newtons third law regarding equal and opposite force?
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    Distance in Electric versus Gravitational potential energy

    Ok, so as the distance increases the value gets closer to zero, and this means the electric potential energy is increasing. So why when we calculate the gravitational potential energy using the formula GPE=m*h*g, does the negative value get further away from zero as the distance above Earth...
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    Distance in Electric versus Gravitational potential energy

    The positive negative is the one I am considering already but its more that one I can't understand. The positive positive situation pretty much makes sense to me. So, if the negative value is decreasing as the distance decreases, does that mean that infinitely far away means infinite negative...
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    Distance in Electric versus Gravitational potential energy

    I don't know what you mean by local version.
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    How is V1 deduced to be zero in the last step here?

    Ah yes. Ok, I am left with 2V1v2 = 0. Obviously the struck ball is going to be moving so it cannot be the one which ends up with a velocity of zero, but is there any other logical or mathematical method of deducting which of the two balls will be the one which will have zero velocity...
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    Distance in Electric versus Gravitational potential energy

    Homework Statement Consider the equations for electric potential energy: and gravitational potential energy: GPE=m*g*h In the case of GPE, the potential energy increases as the distance between the two objects increases. This makes sense (to me), as the greater distance between the Earth...
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    How is V1 deduced to be zero in the last step here?

    When I do (v1+v2)2=v12+v22, after taking the root on both sides I get get v1+v2=v1+v2. What am I doing wrong?
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    How is V1 deduced to be zero in the last step here?

    That v^2 = (v1+v2)^2
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    How is V1 deduced to be zero in the last step here?

    Homework Statement A billiard ball moving at 2 m/s collides (0 degrees) with another of the same weight and at rest, in a perfectly elastic collision. Demonstrate with equations why the balls trade velocities. Homework EquationsThe Attempt at a Solution In the provided explanation, I can...
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    Calculate falling distance when object is already in motion

    Solved it using quadratic formula as suggested. Time to reach observer is 1.251 seconds. Total distance from observer is 425.58 meters. Thanks again for the help here.
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    Calculate falling distance when object is already in motion

    Thanks. Ill get back to this in a few days after going over quadratic formulas again ( and a couple of exams are finished).
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    Calculate falling distance when object is already in motion

    Stuck here:
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    Calculate falling distance when object is already in motion

    I can't . I can't get t1 on its own. I can only get this: Which equation should I start with?
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    Calculate falling distance when object is already in motion

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    Calculate falling distance when object is already in motion

    I changed it