Recent content by chemman218

There are no other problems like this one in the text.

Our professor just told us to use the simple combustion formula... C+ O2 ---> CO2 He gave us some hints saying that we needed to solve for the mass of carbon and oxygen initally burned in order to find the amount of air. He just told us to use the fact that oxygen makes up 20% of air. The...

I actually went back and calculated the grams of O2 and used the molar mass of air which was: 77.5 moles of Carbon x (1 mole of O2 / 1 mole of C) x ( 32 grams of 02 / 1 mole of 02) = 2480 g of O2 2480g of O2 = .20 x ( grams of Air) grams of air = 12400 12400 grams of air x (1 mole of air /...

Homework Statement A power plant burns oil that is 4% ash and 3% Sulfur. At 50% excess air, what particulate (mg/m^3) emissions would you expect? Homework Equations PM in grams = 2.8*.04=.112 grams of PM per 1000 kg of oil Start with 1000 g of oil oil = 4% ash, 3%sulfur, and 93% carbon...

Thank you for the catch. I used the wrong percent to multiply. I used .01 instead of .001. Thank you so much for all your help!

Yes you are correct, but our teacher told us to use 298K.

Yes, it is at STP. I was trying to search the internet for reference on CO levels from automobiles to see if the number I got was correct but could not find anything. Thank you for your help!

Homework Statement An automobile traveling 50 Km/hr emits 0.1% CO from the exhaust. If the exhaust rate is 80 m^3/min, what is the CO emission in grams per kilometer? Homework Equations PV=nrt The Attempt at a Solution flow rate volume of CO...

Thank you so much for the clarification. It makes more sense now to view it in that process.

Homework Statement Supercooled water is water that is liquid and yet BENEATH the freezing point. a) A sample of 131 g of supercooled liquid water freezes to solid ice at a temperature of -8.00 ° C. Using the following, Cp,ice = 38.09 J/molK Cp,liquid = 74.539 J/molK fusH° (at T=0 °...

Got it! Thanks for the help

Okay, thanks for the note on converting j to kj. My main question is how do I know how many degrees of freedom to use in order to complete the equation. My professor sent us an equation to use: the total internal energy is (3+J)/2RT where J is the number of rotational degrees of freedom...

Homework Statement Find the average kinetic energy in kJ/mol (including all degrees of freedom) of one mole of ethane at 410K. Homework Equations 1/2Mu^s = kT/2 u= avg. velocity E=n/2kT N=degrees of freedom The Attempt at a Solution C2H6 degrees of freedom - 3n-6 = 18...