# Is the CO amount I found correct?

## Homework Statement

An automobile traveling 50 Km/hr emits 0.1% CO from the exhaust. If the exhaust rate is 80 m^3/min, what is the CO emission in grams per kilometer?

PV=nrt

## The Attempt at a Solution

flow rate volume of CO =(.8m^3/min)8(1min/.833km)=.960m^3/km*(1000L/1m^3)=960 L/km

PV=nRT
n=((1atm)(960L/km))/((.08206 L*atm/mol*k)*(298K))=39.25 moles/km of CO
39.25moles/km * 28g/mole of CO = 1099.65 g/km

Chestermiller
Mentor
Yes, assuming that those 80 m^3/min are specifically referenced to 1 atm and 298K.

Chet

Yes, it is at STP. I was trying to search the internet for reference on CO levels from automobiles to see if the number I got was correct but could not find anything. Thank you for your help!

Chestermiller
Mentor
Yes, it is at STP. I was trying to search the internet for reference on CO levels from automobiles to see if the number I got was correct but could not find anything. Thank you for your help!
Isn't STP 1 atm and 0 C?

Chet

Yes you are correct, but our teacher told us to use 298K.

gneill
Mentor

## The Attempt at a Solution

flow rate volume of CO =(.8m^3/min)8(1min/.833km)=.960m^3/km*(1000L/1m^3)=960 L/km

Shouldn't that be 0.08 m3/min if it's 0.1% of 80 m3/min?

Thank you for the catch. I used the wrong percent to multiply. I used .01 instead of .001. Thank you so much for all your help!