Is the CO amount I found correct?

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Homework Help Overview

The problem involves calculating the carbon monoxide (CO) emissions from an automobile based on its exhaust rate and concentration of CO in the exhaust. The subject area includes gas laws and emissions calculations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculations related to the flow rate of CO and its conversion to grams per kilometer. There are questions regarding the assumptions of standard temperature and pressure (STP) and the accuracy of the initial flow rate used in the calculations.

Discussion Status

The discussion is ongoing, with participants providing feedback on the calculations and clarifying assumptions about the conditions under which the measurements are taken. Some participants have pointed out potential errors in the initial calculations and have engaged in verifying the conditions for STP.

Contextual Notes

There is a mention of specific conditions (1 atm and 298K) that were instructed by the teacher, which may differ from standard definitions of STP. Additionally, there is a correction regarding the percentage used in the calculations, indicating a need for careful attention to detail in the problem setup.

chemman218
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Homework Statement


An automobile traveling 50 Km/hr emits 0.1% CO from the exhaust. If the exhaust rate is 80 m^3/min, what is the CO emission in grams per kilometer?

Homework Equations


PV=nrt

The Attempt at a Solution


flow rate volume of CO =(.8m^3/min)8(1min/.833km)=.960m^3/km*(1000L/1m^3)=960 L/km

PV=nRT
n=((1atm)(960L/km))/((.08206 L*atm/mol*k)*(298K))=39.25 moles/km of CO
39.25moles/km * 28g/mole of CO = 1099.65 g/km
 
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Yes, assuming that those 80 m^3/min are specifically referenced to 1 atm and 298K.

Chet
 
Yes, it is at STP. I was trying to search the internet for reference on CO levels from automobiles to see if the number I got was correct but could not find anything. Thank you for your help!
 
chemman218 said:
Yes, it is at STP. I was trying to search the internet for reference on CO levels from automobiles to see if the number I got was correct but could not find anything. Thank you for your help!
Isn't STP 1 atm and 0 C?

Chet
 
Yes you are correct, but our teacher told us to use 298K.
 
chemman218 said:

The Attempt at a Solution


flow rate volume of CO =(.8m^3/min)8(1min/.833km)=.960m^3/km*(1000L/1m^3)=960 L/km

Shouldn't that be 0.08 m3/min if it's 0.1% of 80 m3/min?
 
Thank you for the catch. I used the wrong percent to multiply. I used .01 instead of .001. Thank you so much for all your help!
 

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