Recent content by ConorDMK
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System of two spin 1/2 particles in an external magnetic field
Oh yeah, of course, thank you! It's been a while since I've done this stuff. So I use, which makes sense as to why the hint says to use Pauli Matrices and Spinors.- ConorDMK
- Post #3
- Forum: Advanced Physics Homework Help
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System of two spin 1/2 particles in an external magnetic field
So what I'm not sure on, is calculating the matrix elements for part (iii) with Pauli spinors and Pauli matrices, and then finding the form of the corresponding states. As I don't see how using the hint helps. The following is using the eigenvalues of the spin-operators. Provided what I...- ConorDMK
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- Field Magnetic Magnetic field Particles Spin Spin 1/2 System
- Replies: 2
- Forum: Advanced Physics Homework Help
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Calculating Count Rate for Neutron Beam Detection
Thank you very much! I'll keep the advice noted as well. These sorts of questions always trip me up, I guess I just need to be more confident with my workings.- ConorDMK
- Post #3
- Forum: Advanced Physics Homework Help
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Calculating Count Rate for Neutron Beam Detection
Finding the neutrons per second. Uncluttering the question: ##P = 6 \times 10^{7} J/s, E_{1} = 149.7 MeV/event, A = 10^{-4} m^{2}, R = 5 m ##. Number of events per second = ##\frac{P}{E_{1}}## = escaping neutrons per second Area of ##5m## sphere around reactor = ## 4 \pi R^{2} ## Fraction of...- ConorDMK
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- Beam Detection Neutron Nuclear Rate
- Replies: 2
- Forum: Advanced Physics Homework Help
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Grad of a Scalar Field: Computing ∇T in Spherical Coordinates
Sorry, I kept thinking ∇ had to be a vector. (∇T)r = (∂T/∂r) (∇T)θ = (∂T/∂θ)(1/r) (∇T)φ = (∂T/∂φ)(1/(r*sin(θ)))- ConorDMK
- Post #6
- Forum: Advanced Physics Homework Help
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Grad of a Scalar Field: Computing ∇T in Spherical Coordinates
(∇T)r(dl)r = (∂T/∂r)(dr/dr)rˆ = (∂T/∂r)rˆ (∇T)θ(dl)θ = (∂T/∂r)(dθ/dθ)θˆ = (∂T/∂θ)(1/r)θˆ (∇T)φ(dl)φ = (∂T/∂φ)(dφ/dφ)φˆ = (∂T/∂φ)(1/(r*sin(θ)))φˆ ∇T(r) = (∇T)r(dl)r + (∇T)θ(dl)θ + (∇T)φ(dl)φ = (∂T/∂r)rˆ + (∂T/∂θ)(1/r)θˆ + (∂T/∂φ)(1/(r*sin(θ)))φˆ This is what I had before, but I didn't think...- ConorDMK
- Post #4
- Forum: Advanced Physics Homework Help
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Grad of a Scalar Field: Computing ∇T in Spherical Coordinates
Homework Statement Let T(r) be a scalar field. Show that, in spherical coordinates ∇T = (∂T/∂r) rˆ + (1/r)(∂T/∂θ) θˆ + (1/(r*sin(θ)))(∂T/∂φ) φˆ Hint. Compute T(r+dl)−T(r) = T(r+dr, θ+dθ, φ+dφ)−T(r, θ, φ) in two different ways for the infinitesimal displacement dl = dr rˆ + rdθ θˆ + r*sin(θ)dφ...- ConorDMK
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- Field Grad Scalar Scalar field
- Replies: 7
- Forum: Advanced Physics Homework Help
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Image formed by lens-water-mirror system
That's the line of thinking that we decided to go down in the end. And having done that, I decided to do the full algebraic expression for the final image and final magnification anyway, just to annoy the people marking it. I feel like Dr Frankenstein.- ConorDMK
- Post #3
- Forum: Introductory Physics Homework Help
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Image formed by lens-water-mirror system
Homework Statement A symmetric, double-convex, thin lens made of glass with n = 1.52 has a focal length in air of 40 cm. The lens is sealed into the opening in the left-hand of a tank filled with water (n = 4/3). At the right-hand end of the tank is a plane mirror 90 cm from the lens. Find the...- ConorDMK
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- Image System
- Replies: 3
- Forum: Introductory Physics Homework Help
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What is the Internal Energy of 158 moles of CO2
Got it, thank you very much.- ConorDMK
- Post #3
- Forum: Introductory Physics Homework Help
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What is the Internal Energy of 158 moles of CO2
Homework Statement A gas bottle contains exactly 158 moles of carbon dioxide CO2. Find the change in the internal energy of this much CO2 when it is cooled from 36C down to exactly 25C at a constant pressure of 1 atm. The gas can be treated as an ideal gas with γ=1.289. The gas constant reads...- ConorDMK
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- Co2 Energy First law of thermodynamics Internal Internal energy Moles
- Replies: 3
- Forum: Introductory Physics Homework Help
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Descending mass on rope attached to wheel
t=√[(2(57kg)(12m)+2(9.6kgm2)(12m/0.3m)2)/((57kg)(9.8N/kg)(12m))] t=2.65s- ConorDMK
- Post #13
- Forum: Introductory Physics Homework Help
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Descending mass on rope attached to wheel
so if I continue with mgh=0.5m(2h/t)2+0.5I(2h/(rt))2 I should get the correct answer?- ConorDMK
- Post #11
- Forum: Introductory Physics Homework Help
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Descending mass on rope attached to wheel
suvat: s=t(v+u)/2 as u=0 for both v=2s/t so v=2h/t and ω=2h/(rt) Correct? or should they be without the 2?- ConorDMK
- Post #9
- Forum: Introductory Physics Homework Help
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Descending mass on rope attached to wheel
Energy before: Etotal=mgh Energy after: Etotal=0.5mv2+0.5Iω2 using ω=h/(rt) and v=2h/t mgh=0.5m(2h/t)2+0.5I(h/(rt))2 t2=(2mh2+0.5I(h/r)2)/(mgh) t=√[(2mh2+0.5I(h/r)2)/(mgh)] Putting in the values t=√[(2(57kg)(12m)2+0.5I(12m/0.3m)2)/((57kg)(9.8N/kg)(12m))] t=1.90s to 2 decimal places...- ConorDMK
- Post #7
- Forum: Introductory Physics Homework Help