Recent content by Frankenstein19

TL;DR Summary: Used M1V1=M2V2 but am unsure if formula applies I feel like I could use M1V1=M2V2 but the 18% by weight ammonium hydroxide is confusing me so much. Density of ammonium hydroxide 18% is 0.926 g/cm3 18%V1=16mg/L*200L (18mg ammonium/100 mg of total solution) * V1 = 3,200mg...

If I have 100mL inside a glass with a closed cap. I take the cap off, measure DO, put the cap back on and decrease the temperature 20 degrees. No agitation of any sort. Does the DO increase?

For air for example at conditions 150 F and 125 psig, density is 0.61lb/ft3 At standard conditions it's 0.0765lb/ft3 If I convert 500 cfm to scfm, does this mean I should multiply by 0.0765lb/ft3*60min/hr to convert to lb/hr?

I've included the problem statement and a bit about the function but my main issue is with the equation after "then" and the one with the red asterisk. I don't understand why the Laplace transform for a u(t)*e^(-t/4) isn't (1/s)*(1/(s+1/4)). The book I am reading says it's(1/(s+1/4)).

Homework Statement What factors affect enthalpy of fusion? Also, does structure affect enthalpy of fusion?

Homework Statement I need to find the distribution coefficients for acetic acid of various concentrations in a ether/water system, but I'm not too sure of my calculations Homework Equations To get the concentrations of acetic acid in the aqueous phase I took the ([average concentration of...

Homework Statement Homework Equations The Attempt at a Solution [/B] My questions: 1. By resultant force, does that mean the force exerted on the side of the water + force exerted on side of the oil? Because I'd think that the force on the side of the water would be different than the...

Homework Statement When 100.0 mL of weak acid HA was titrated with 0.09381M NaOH, 27.63mL were required to reach the equivalence point. The pH at the equivalence point was 10.99. What is the pKa of HA Homework Equations pH=pKa+log([A]/[HA] [OH]-10^(-pOH) The Attempt at a Solution...

Yikes. ok so if i apply kcl on va i between the resistors i'd have: (va+24)/3ohm + (voc-va)/6ohm=1.33va since i have 2 variables i need 2 eq and doing kcl on voc: (voc-va)/6ohm -24V/9ohm= 1.33va I get that va is 2.29 and voc is 36.58

Homework Statement [/B] Homework EquationsThe Attempt at a Solution First I found the equivalent resistance since the 3 ohm resistor and 6 ohm resistor are in series. 9ohm. Then I did chose the node where the arrow points to as Voc, which is also va. KVL: (va+24V)/9ohm=1.33va I get va to be...

Yes...? If there's a resistor in between does that make them stop being in parallel?

Homework Statement [/B] I'm going exercises and I understand that if the circuit is short circuited that R=10 ohm is 0. (Trying to find Thevelin R in all of these btw) But then I ran across this one where when it's short circuited, isc is found using the current divider principle and it's...

30! Haha bless your soul for spoon feeding this to me. But I'm still a little confused as to why I'd suppose there was a source connected to the output terminals. I wasn't doing that with previous exercises. (I'll try it though to confirm)

Sorry if I'm nor using correct terminology but through the 20 an 10 ohm resistor?

None? It'll just look like a T