The discussion focuses on calculating the equivalent resistance in a Wye formation circuit while determining the Thévenin resistance by zeroing the sources. Participants clarify that after suppressing the current source, the only current path available is through the 20 Ω and 10 Ω resistors, leading to an equivalent resistance of 30 Ω. The conversation emphasizes the importance of visualizing a voltage or current source connected to the output terminals to understand the circuit's behavior and resistance. Techniques for analyzing more complex networks with controlled sources are also mentioned.
PREREQUISITESElectrical engineering students, circuit designers, and anyone involved in circuit analysis and design who seeks to deepen their understanding of equivalent resistance and Thévenin's theorem.
None? It'll just look like a Tgneill said:
Yes, but suppose you were to apply a voltage (or current) source across the two output terminals. What path or paths could current follow? Remember, a "circuit" implies a closed path (loop).Frankenstein19 said:
Sorry if I'm nor using correct terminology but through the 20 an 10 ohm resistor?gneill said:
Correct! The 5 Ω resistor, being disconnected at one end, is unable to pass a current through it. So the only path available is the one you've identified.Frankenstein19 said:
30! Haha bless your soul for spoon feeding this to me. But I'm still a little confused as to why I'd suppose there was a source connected to the output terminals. I wasn't doing that with previous exercises. (I'll try it though to confirm)gneill said:
The idea is that the network presents a certain resistance at the output terminals. A resistance can pass current through it. Hence, if you imagine that there is a source connected across it, then only the paths that can pass current can be involved in the net resistance.Frankenstein19 said:
