- #1
Frankenstein19
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Homework Statement
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I'm going exercises and I understand that if the circuit is short circuited that R=10 ohm is 0. (Trying to find Thevelin R in all of these btw)
But then I ran across this one where when it's short circuited, isc is found using the current divider principle and it's R1/(R1+r2), why doesn't R1 turn to zero?