I'm not entirely sure. My professor said that I should use the equation (I_0)cos^2(Φ/2) with I_0 equaling the intensity at the origin of the two slit model. So I'm assuming that the 4(I_0) has something to do with the the intensity one slit would produce. We havent done single slits so I'll have...
I'm still on part a.
I think that i may have the wrong equation for intensity.
I'm not sure I'm using the right numbers for the "first minimum".
I started with getting the wavelength
since the first minimum occurs at m = 0.5 I multiplied the distance to the first minimum by 2 to get...
Sorry for the long wait time. Schools being chaotic since they're trying to figure out how to put everything online as a stop gap for the Corona Virus. Removing the "." did not work although I'm sure what you suggested will come in handy. I'm going to see if I can find a professor or Grad...
changed the location where the simulation is storing Lab4.vwf.vt to qsim/work and fixed it to the point where the simulation completes but now wont open the completed file automatically. I'm going to check and see if it opens manualy in a bit but the new screen is
I can open Lab4.vwf.vt...
editide line 4 of the model sim script from
vlog -work work Waveform.vwf.vt
vlog -work work Lab4.vwf.vt
reduced the error to
but it should be noted that the flow progress readout is way, way longer than it was. I don't know if I've gotten closer to getting this to work or if I've f'ed...
Homework Statement:: None. This is part of implementing a project and not an actual question. It's a technical problem or equipment failure.
Relevant Equations:: The Code I get is;
Error: (vlog-7) Failed to open design unit file "Waveform.vwf.vt" in read mode.
[Mentor Note -- moved to the...
I was asked to use De Morgans law to find the complement of a particular equation, I applied the law correctly and simplified my solution down to
I ran the problem through a boolean simplifier to check my work...
Thank you. It turns out I had the potentiometer wired wrong. It was my first time using one and I didn't realize that the resistance between the two inputs was the total value of the internal resistor. After some sleep I got my circuit working and I'm having a lot of fun with it.
Thank you. It turns out I had the potentiometer wired wrong. I figured out how to use it right after I checked the resistance between each leg. My circuit is working properly now and I'm having a great time with it.
The problem is that I need a single output that will range from -2 to +2 v. Unfortunately I don't know how to accomplish that with a single potentiometer. That's why I had that strange setup before. How do I combine the separate voltages into a single output?
I need to create a powersupply that takes in a +5 and -5v and has an adjustable output that varies between -2 and +2 v using one potentiometer.
I already came up with a design myself but it did not work. I need some help figuring this out.
I think my idea for how to get specific positive or...