An insulated Thermos contains 122 g of water at 91°C. You put in a 13.7 g ice cube at 0°C to form a system of ice + original water.
Use mc(ΔT) |water + mc(ΔT) |ice + Lm |ice = 0
Final T = [(m*c*T) |water + (m*c*T) |ice - (L*m) |ice] / [m*c |water + m*c |ice]
Final T =...
I'm really confused.
Why are there two boundary conditions for an single variable integration?
I know z and h are the same parameter.
If I set P=0 and z=h=L in the final equation, I get L = 1.3L2/-1.3L, which simplifies to -1.3L2=1.3L2 How does this help?
Well, dP/dz = ρg can be rearranged to dP = gρ(z)dz and integrate ρ(z) from 0 to h?
The result is P = g(-1.3/(2L)*h2+1.3h), and now I can solve for L = (1.3h2)/(2P/g-1.3h)
But what I can plug in for h?
I don't understand how to express the density as a function of z...
y = mx + b
ρ(z) = -1.3/(z max) * z + 1.3 ? How does this integrate into anything useful?
Homework Statement
Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.
What would be the height of the atmosphere if the air density decreased linearly to zero with height?
Homework Equations
P = ρgh
The Attempt at a Solution
Really not sure...
Wow. All I can say is, stay off drugs, kids.
edit: So I ended up with a value of 1.016e-22, and it's STILL not right. I've run out of chances now, but I'm still interested in knowing what I'm doing wrong here.
So, ƩFx = F + 8F + 8F/4 and ƩFy = 4F/4
ƩF = (11F^2+F2)1/2
ƩF = (122F2)1/2
F = k(4e)(e)/(.012) = 4ke2*.012
ƩF = 1.0168e-30
This doesn't seem right since it's 7 degrees off my previous calculations.
Homework Statement
In the figure below, six charged particles surround particle 7 at radial distances of either d = 1.0 cm or 2d, as drawn. The charges are q1 = +8e, q2 = +8e, q3 = +e, q4 = +8e, q5 = +8e, q6 = +4e, q7 = +4e, with e = 1.60 10-19 C. What is the magnitude of the net electrostatic...
Homework Statement
In the figure below, six charged particles surround particle 7 at radial distances of either d = 1.0 cm or 2d, as drawn. The charges are q1 = +8e, q2 = +8e, q3 = +e, q4 = +8e, q5 = +8e, q6 = +4e, q7 = +4e, with e = 1.60 10-19 C. What is the magnitude of the net electrostatic...