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## Homework Statement

In the figure below, six charged particles surround particle 7 at radial distances of either d = 1.0 cm or 2d, as drawn. The charges are q1 = +8e, q2 = +8e, q3 = +e, q4 = +8e, q5 = +8e, q6 = +4e, q7 = +4e, with e = 1.60 10-19 C. What is the magnitude of the net electrostatic force on particle 7?

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1-7-3-4

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## Homework Equations

F = k(q1)(q2)/(r^2)

k = 8.99e9

## The Attempt at a Solution

I split this up into x and y components, and then figured out the sum.

For the x, ƩF = |k(q7*q1)/(r^2) - k(q7*q3)/(r^2) - k(q7*q4)/(4(r^2))|

This simplifies to: |[k(q7)/(r^2)]*[q1-q3-q4/4]|

and so ƩF = |[4ke/(.01^2)]*e(8-1-8/4)| = 4ke/.0001*5e = 20k(e^2)/.0001

I used the same process for the y component. 2 and 5 cancel out since they have the same distance and charge, so the only charge I needed to calculate was for 6. F = k(q7)(q6)/(4(r^2))

This simplifies.. F = k(6e)(4e)/((4)(.0001)) = 6k(e^2)/.0001

Now the net charge is ([20k(e^2)/.0001]^2 + [6k(e^2)/.0001]^2)^.5

Simplify this to [436(k^2)(e^4)/(10^-8)]^.5 which comes out to 4.8055e-23, which webassign says is incorrect.