Recent content by gtfitzpatrick

Cant get my head around the order of the upper and lower bounds for this, Is it always the higher take away the lower?

Hi, Thanks a million for the response. Do I not need the mean and the standard deviation, To calculate the z scores? Using the information i have is the only way can do by adding them all up?

Hi, Trying to figure this out any ideas as to what I am doing wrong? Thanks all

Homework Statement A club has only 8 women and 6 men as members. A team of 3 is to be chosen to represent the club. In how many ways can this be done if there is to be at least one woman on the team. Homework EquationsThe Attempt at a Solution I can do this 2 ways, first 1w2m + 2w1m + 3m0m...

its for an exam, could possibly come up. But the proof is very long to learn off! :(

hi christoff, Thanks for reply. The reson why i didnt put in the Proof of the Cauchy integral formula as it is very long and hard to remember. Do you know anywhere i can get a hardy version that i could throw in?

Homework Statement Prove that if f(z) is analytic over a simply connected domain containing a simple closed curve C abd Z_{0} is a point inside C then f'(z_{0}) = \frac{1}{2i\pi} \oint_{c} \frac{f(z)}{(z-z_0)^2} dz Homework Equations The Attempt at a Solution from the definition...

Homework Statement Prove from first principles that f(z) = \overline{z}^2 is not differentiable at any point z ≠ 0 Homework Equations The Attempt at a Solution So i guess i Have to show \stackrel{lim}{h\rightarrow0} \frac{f(z+h)-f(z)}{h} is equal to zero right...

getting back to this... So my equation for an ellipse is\frac{x^2}{1^2} + \frac{y^2}{2^2} = 1 so parametizing this I get x=cos\theta and y=2sin\theta and from green the area is \frac{1}{2}\int^{2\pi}_{0} cos\theta(2cos\theta)-sin\theta(-2sin\theta d\theta = \frac{1}{2}\int^{2\pi}_{0} 2(1)...

\oint_C \vec H \cdot d\vec r =\oint_C \frac{dμ}{dx}\, dx + \frac{dμ}{dy}\, dy = \int\int\frac{d^2μ}{dxdy}-\frac{d^2μ}{dxdy} dxdy = 0 but this can only be true if \oint F.dr = \oint G.dr qed?

No. in a word. I thought i might be able to work something out using greens theorem(as the curve is closed) but its not working out...

Hi I am doing a similar problem so sooner than start a new thread... \oint_C \vec H \cdot d\vec r =\oint_C \frac{dμ}{dx}\, dx + \frac{dμ}{dy}\, dy ?

The arc length is\pi r |f(z)| \leq A|z|^{-k} the semicircle is given by |z| = R so for k>1, if the value of R gets bigger, then the value of \frac{A}{|z|^{k}} gets smaller so as R\rightarrow\infty then |f(z)| \rightarrow 0 I guess that's what ther're saying but i guess i better try...

Hi! Sorry about the multiple thread but I called it jordans lemma then thought, it might have nothing to do with it but I couldn't delete the thread after creating it! I haven't done the estimation lemma but I looked it up Let f : U\rightarrowC be continuous (where U is some subset of C)...

Homework Statement Suppose that f is continuous and that there exist constants A,B ≥ 0 and k>1 such that |f(z)|≤A|z|−k for all z such that |z|>B. let CR denote the semicircle given by |z| = R, Re(z) ≥ 0. Prove that limR→∞∫f(z)dz=0 Homework Equations The Attempt at a Solution I...