Cauchy integral formula(is this enough of a proof?)

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Homework Help Overview

The discussion revolves around proving a specific result related to the Cauchy integral formula in complex analysis. The original poster attempts to show that if a function f(z) is analytic in a simply connected domain containing a closed curve C, then the derivative at a point inside C can be expressed using an integral involving f(z).

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the validity of the original poster's proof and question whether the proof of the Cauchy integral formula itself needs to be included. There is also a focus on the conditions under which limits and integrals can be interchanged.

Discussion Status

Some participants provide feedback on the proof's assumptions and the necessity of proving the Cauchy integral formula. Others share their experiences regarding exam preparation and the importance of understanding key theorems, suggesting that the original poster consider how to approach learning the proof.

Contextual Notes

The original poster mentions that the proof of the Cauchy integral formula is lengthy and challenging to memorize, which raises concerns about its relevance for an upcoming exam.

gtfitzpatrick
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Homework Statement



Prove that if f(z) is analytic over a simply connected domain containing a simple closed curve C abd Z_{0} is a point inside C then f'(z_{0}) = \frac{1}{2i\pi} \oint_{c} \frac{f(z)}{(z-z_0)^2} dz

Homework Equations





The Attempt at a Solution


from the definition of a derivative we have f'(z_{0}) =\stackrel{lim}{h\rightarrow0} \frac{f(z_0 +h) - f(z_0)}{h}
the cauchy integral formula states f(z_{0}) = \frac{1}{2i\pi} \oint_{c} \frac{f(z)}{(z-z_0)} dz and so f(z_{0}+h) = \frac{1}{2i\pi} \oint_{c} \frac{f(z)}{(z-z_0 +h)} dz

then subing the last 2 into the first one i get f'(z_{0}) = \stackrel{lim}{h\rightarrow0} \frac{1}{2i\pi} \oint_{c} \frac{1}{h} (\frac{f(z)}{(z- z_0 - h)} - \frac{f(z)}{(z-z_0)} )dz

=f'(z_{0}) = \stackrel{lim}{h\rightarrow0} \frac{1}{2i\pi} \oint_{c} (\frac{f(z)}{(z- z_0 - h)(z-z_0)} )dz
on[/b]

= \frac{1}{2i\pi} \oint_{c} \frac{f(z)}{(z-z_0)^2} dz

is this enough of a proof or would i also have to prove cauchys integral formula?
 
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The proof looks fine, except for two things:

1. It assumes you already know the first version of the Cauchy Integral Formula (eg. f(z_0)=\frac{1}{2\pi i}\int_C \frac{f(z)}{z-z_0}dz). I might be misunderstanding your question at the bottom, but if you haven't already proven this result, then you must do so before invoking it in your proof.

2. One line before your conclusion, you permute the limit with the integral. Are you sure you can do that? By uniform convergence, if
g_n(z)=\frac{f(z)}{(z-z_0-h_n)(z-z_0)}
converges uniformly to
<br /> \frac{f(z)}{(z-z_0)^2}
for every sequence h_n\rightarrow 0, then you can permute the limit and the integral sign. Do you have this result? If you aren't looking for a rigorous proof, then what you have is enough. However, in general, you cannot permute the integral and limit like that.
 
hi christoff,
Thanks for reply. The reson why i didnt put in the Proof of the Cauchy integral formula as it is very long and hard to remember. Do you know anywhere i can get a hardy version that i could throw in?
 
That really depends on what this is for. If this is for homework, then any complex analysis textbook will cover it, and you should be able to find a proof and figure it out on your own. In that case however, you've likely covered the (first) integral formula in class, so you are probably free to say "by the (first) Cauchy Integral Formula..."
 
its for an exam, could possibly come up. But the proof is very long to learn off! :(
 
Ah, that's unfortunate. I remember when I was taking my second course in real analysis, our professor offered us a recommended study guide for the final exam. It included the suggestion: "Know how to prove all of the key theorems". Very helpful.

In that case, you will have to weigh the risks and decide if you want to learn the proof, or skip it and hope that it doesn't come up in an exam. In that situation, I like to review the proof enough to come up with an outline - not necessarily every little step, but enough of a "skeleton" so that I can hopefully figure it out in the moment. It works for me...

Good luck!
 

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