Recent content by heartshapedbox

Homework Statement A 1.0kg of ice at 0◦C, 3.0kg of water at 0◦C, and 5.0kg of iron at temperature T are placed in a sealed and insulated container. cFe =400J/ kg◦C ,cWater=4200J/ kg◦C , cIce= 2000 J/ kg◦C latent heat for ice is 3.3×105 J . The equilibrium temperature is 20◦C.Homework...

Yes that's the distance!

Still unsure how the attempt to solve is wrong, help please?

−1.2E−10i-hat −5.1E-11 j-hat Correct answers...

Homework Statement There are three particles; 1) 26kg at 12i-hat 2)13kg at -5j-hat 3)13 kg at 5j-hat A) What is the gravitational force on the 26kg mass due to the 13kg mass at -5j-hat Homework Equations F= GMm/r^2 The Attempt at a Solution A) IN COMPONENTS; Y Component...

Homework Statement see attachment ***indicates correct answer Homework Equations F=ks The Attempt at a Solution I do not understand how this works, and I haven't been able to find any examples of this.

Ok thank you, I believe I understand. Right hand in direction of velocity, curl towards r, L is out of the page, so k direction. Right hand in direction of velocity, curl towards F (there is the force of B and the centripetal force) they point in opposite directions, so they cancel, making...

the correct answer is marked by "***" :)

Awesome :) Sorry you had correctly told me what to do at the start, but I misunderstood. Thank you :)

Great thanks so much guys, @Kaura and @gneill :) I understand it easily now!

This is the complete problem, I do not know how to do #3. :) Thanks!

This is what i have done :) The y component is giving me a hard time but I have found the x component. j stands for y and i stands for x.

Homework Statement A particle of mass 52[kg] is at 5.0[m]ˆi a particle of mass 13[kg] is at 12[m]j, and a particle of mass 13[kg] is at −12[m]jˆ. What is the gravitational force on the 52[kg] mass due to the mass at 12[m]jˆ? answer: −1.0 × 10−10[N]ˆı + 2.5 × 10−10[N]jˆHomework Equations...

Homework Statement At the instant illustrated, which best describes the angular momentum of the ball and net torque on the ball, as measured around the origin? L⃗ is in the kˆ direction, ⃗τ is 0. Homework Equations torque= (F)x(r) Tension in rope= (mv^2/r)+qvbThe Attempt at a Solution I am...

Ok i see what i did wrong, lol, long day. Total initial momentum: 40i 5kg mass final momentum: 12i, -16j Due to conservation of momentum: 6kg final momentum: 28i, 16j sqrt((28/6)^2+(-16/6)^2) final speed: 5.4m/s