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Latent heat and specific heat in insulated container

  1. Feb 10, 2017 #1
    1. The problem statement, all variables and given/known data
    A 1.0kg of ice at 0◦C, 3.0kg of water at 0◦C, and 5.0kg of iron at temperature T are placed in a sealed and insulated container. cFe =400J/ kg◦C ,cWater=4200J/ kg◦C , cIce= 2000 J/ kg◦C

    latent heat for ice is 3.3×105 J .
    The equilibrium temperature is 20◦C.


    2. Relevant equations
    Q=mcΔT
    Q=ml

    3. The attempt at a solution
    0=Qice→water+Qice+Qwater+Qiron
    =ml(ice)+mcΔT(ice)+mcΔT(water)+mcΔT(iron)
    =(1.0)(330000)+(1.0)(2000)(20-0)+(3.0)(4200)(20-0)+(5.0)(400)(20-Ti)
    Ti=331°C

    BUT the answer says it should be 353°
     
  2. jcsd
  3. Feb 10, 2017 #2

    Orodruin

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    Once you have melted the ice, it is water.
     
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